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Kobotan [32]
3 years ago
12

Someone answer all 1-10 please

Mathematics
1 answer:
jarptica [38.1K]3 years ago
8 0
1. -3/2
2. 2
3. 1/2
4.0
5. 1/2
6. -3/4
7. -1/4
8. -8/11
9. 0
10. -1/5
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Find the area of the sector round your answer to the nearest 10th
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Step-by-step explanation:

The area of the whole circle is ...

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The measure of HMQ is (4x – 20)° ?
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Help 80 points A concrete planter is formed from a square-based pyramid that was inverted and placed
Rufina [12.5K]

Answer:

<h3>(A)</h3>

The slant height of the pyramid refers to the height of a face of the pyramid.

Notice that each slant height forms a right triangle like the image attached shows, where the hypothenuse is the slant height. Additionally, the bottom leg is 1 yard, because is half of the base side, and the other leg is 2 yard. Using Pythagorean's Theorem, we have

h^{2} =1^{2} +2^{2} \\h=\sqrt{1+4}=\sqrt{5}

Therefore, the slant height is the square root of 5 yard.

<h3>(B)</h3>

The surface area of the composite figure is the sum of the surface area of both volumes.

<h3>Surface area of the cube.</h3>

S_{cube}=5(2yd)^{2}  =20 yd^{2}

Notice that we only included 5 faces of the cube, that is because the sixth is the base of the pyramid, so if we include it here, we would have the wrong total surface area.

<h3>Surface area of the pyramid.</h3>

S_{pyramid}=\frac{1}{2}pl

Where p is the perimeter of the base and l is the slant height.

S_{pyramid}=\frac{1}{2}(8yd)(\sqrt{5}yd )=4\sqrt{5}yd ^{2}

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S_{total}=20yd^{2} +4\sqrt{5} yd^{2} \approx 29.94 yd^{2}

<h3>(C)</h3>

To find the cubic yards of concrete, we need to subtract the volume of the figures, because the concrete would be inside the space between the cube and the pyramid.

V_{concrete}=V_{cube}  -V_{pyramid}=l^{3}-  \frac{1}{3}l^{2}h

Where l=2yd and h=2yd

V_{concrete}=2^{3}-\frac{1}{3}(2)^{2} (2)=8-\frac{8}{3} \approx  5.33 yd^{3}

Therefore, it would be needed 5.33 cubic yards of concrete to make the planter.

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What is 14 14/15 as a demical
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