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elixir [45]
3 years ago
6

I need help with this khan academy question

Mathematics
1 answer:
Bond [772]3 years ago
8 0
That will be =3x10 with the baby 3 on top of the 10 and that also equals 3000
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A bus uses 50 liters of petrolfor 1-000 km of journey' t3l Find the amount of petrol needed for 400 km journey'
Amanda [17]

Answer:

hijjijkkkmmkmjjjjjjjjjijjji

4 0
3 years ago
3•n = 6 will mark brainlist if answered correctly
nata0808 [166]

Answer:

2

Step-by-step explanation:

3 * n = 6

/3         /3

n = 2

7 0
3 years ago
Read 2 more answers
Find the dimensions of a rectangle whose perimeter is 42 m and whose area is 104 m squared
julia-pushkina [17]
P=42 m
1/2 of P=21
1/2 of P= l+w
21=13+8
A=13×8
A=104 m^2. As a result, the length is 13 m, and the width is 8 m. Hope it help!
6 0
3 years ago
2x + 3 = 7<br><br>418 = -22a<br><br>What are the VARIABLES in these two equations?​
Anika [276]

Answer:

x=2

a=19

Step-by-step explanation:

2x+3=7

2x+3-3=7-3

2x=4

2x/2=4/2

x=2

418=-22a

418/(-22)=-22a/(-22)

19=a

4 0
3 years ago
Read 2 more answers
A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard,
crimeas [40]

Answer:

Landscaping Company will charge $80 for Neighbor yard.

Step-by-step explanation:

Given:

Charges of Mr. Jones = $52

Length of Mr. Jones yard = 65 feet

Width of Mr. Jones yard = 40 feet

Now we will find the area of Mr. Jones yard.

Yard is basically in rectangular form.

Hence we can;

Area of yard is equal to product of length of the yard and width of the yard.

Framing in equation we get;

Area of Mr. Jones Yard = 40\times 65 = 2600\ ft^2

Now Mr. Jones was charged $52 for a yard having Area 2600 sq. ft.

So we will find the per sq. ft charge applied by the company.

Per sq. ft charge will be equal to Charges of Mr. Jones divided by Area of Mr. Jones Yard.

Framing in equation form we get;

Per sq. ft charge = \frac{52}{2600} = \$0.02

Hence the Landscaping company charge Mr. Jones at $0.02 per sq.ft.

Now Given:

Length of Neighbor yard = 80 ft.

Width of Neighbor yard = 50 ft.

We need to find the Charges on Neighbor based on charges applied on Mr. Jones.

First we will find the Area of Neighbors yard we get;

Area of Neighbors yard = 80 \times50 = 4000\ ft^2

Charges of Neighbor yard will be equal to charges Landscaping company for per sq. ft multiplied by area of Neighbors yard.

Framing in equation form we get;

Charges of Neighbor yard = 0.02\times 4000 = \$80

Hence Landscaping Company will charge $80 for Neighbor yard.

8 0
3 years ago
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