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aliina [53]
3 years ago
8

Which of the following expressions are polynomials?

Mathematics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

1,3 and 5

Step-by-step explanation:

1) -2(7x + 1) − 5(3x2 + 3x + 2)

= -14x - 2 - 15x^2 - 15x - 10

= -15x^2 - 29x - 12

2) (5x2 − 10x + 8) − (10x2 + 19x + 20)

= 5x^2 - 10x + 8 - 10x^2 - 19x - 20

= -5x^2 -29x - 12

3) (-7x2 − 21x + 13) − (8x2 + 8x + 25)

= -7x^2 - 21x + 13 - 8x^2 - 8x - 25

= -15x^2 - 29x - 12

4) (-19x2 − 4x - 7) + (4x2 + 25x − 5)

= -15x^2 + 21x - 12

5) (-17x2 + 2x − 3) + (2x2 − 31x − 9)

= -15x^2 -29x - 12

6) -2(4x − 15) − 3(5x2 + 7x + 6)

= -8x + 30 - 15x^2 - 21x - 18

= -15x^2 - 29x + 12

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" Negative Two "

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I am really confused about this question for math.. any help would be really appreciated:
Elina [12.6K]

y= (\frac 1 4 )^x

A reflection about the x axis, about y=0, is the mapping (x',y')=(x,-y) so

y'= -y = - (\frac 1 4)^{x'}

A dilation of 2 is the mapping (x'',y'')=(2x', 2y')

So

x'=x''/2, y'=y''/2

y''/2= - (\frac 1 4)^{x''/2}

y'' =  - 2((\frac 1 4)^{1/2})^{x''}

y''= - 2(\frac 1 2)^{x''}

We can rewrite that without the primes and combine the powers of 2.

y =  - 2^{1-x}

Let's graph these and see if we're close,

Plot y= (1/4)^x, y= - (1/4)^{x}, y = - 2^{1-x}

6 0
3 years ago
The proportion of items in a population that possess a specific attribute is known to be 0.45. a. If a simple random sample of s
yanalaym [24]

Answer: 0.05

Step-by-step explanation:

  • Sampling error is the error occurs by considering sample for study instead of entire population.

Given : The proportion of items in a population that possess a specific attribute is known to be 0.45.

Sample size : n= 100

Sample proportion of items in a population that possess a specific attribute : \hat{p}=0.48

Now, the formula to find the sampling error :

\text{Sampling error} =\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

\text{Sampling error} =\sqrt{\dfrac{0.48(1-0.48)}{100}}

=\sqrt{\dfrac{0.48(0.52)}{100}}\\\\=\sqrt{0.002496}\approx0.05

Hence, the sampling​ error =0.05

4 0
3 years ago
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