The displaced volume of the water, because of the submersion of the object, is equal to the volume of the object.
So to find the volume of the object we calculate the difference in volume of water:
33.1-25.1 = 8 ml
Since 1 mL of water has the volume of 1cm^3, then the volume of the object is 8 cm^3.
The density of the object is found by the formula:
density= mass/volume= (3 g) / (8 cm^3) = 3/8 (g/cm^3)= 0.375 g/cm^3
Answer: 0.375 g/cm^3
Answer:
nope
Step-by-step explanation:
Answer:
steps below
Step-by-step explanation:
arc QR = 2x57 - 41 = 73
arc PQ = 360 - 73 - 41 - 137 = 109
m∠Q = (41+137) / 2 = 89°
m∠R = (109+137) / 2 = 123°
m∠S = (109+73) / 2 = 91°
check: ∠R+∠p = 123+57 = 180
∠Q+∠S = 89+91 = 180
