Im just about to work one out for you and you just do the same on the rest
Answer:
x ≈ 33.1°
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan x = 
= 
, then
x = 
( ) ≈ 33.1° ( to the nearest tenth )
Answer:
y=-5x-36
Step-by-step explanation:
-66-(-61)= -5
6-5= 1
-5/1= -5
Y=-5x + B
-66= -5(6) + B
-66= -30 + B
-66 + 30 = (-30 +30) + B
-36 = B
Y= -5x-36
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Range is the y values or ouputs
domain is inputs or x vvalues
we can use any x value
but at a certain y value, w can't go below that
find thatminimum
find the vertex
for
ax^2+bx+c
the x value of the vertex is
-b/2a
plug that in to the equaiton to get the y value
-b/2a=-(-6)/(2*2)=6/4=3/2
plug that in
2(3/2)^2-6(3/2)-9
2(9/4)-9-9
9/2-18
4.5-18
-13.5
domain=all real numbers
range=from -13.5 to positive infinity
