Answer:
A diploblast has no mesoderm.
A pseudocoelom has the same functions as a true coelom. In a coelomate, the tissue lining the inner side of the body cavity arises from the same germ layer as the tissue lining the outer side of the body cavity.
Explanation:
Diploblast organisms are the ones that have only two primary germ layers. These organisms have outer ectoderm and inner endoderm but no mesoderm. Example: Cnidarians
A true coelom is derived from mesoderm and is completely lined with tissue derived from mesoderm. The outer and inner linings of the coelom are made of muscle layers that are developed from the mesoderm.
A pseudocoelom is the one that is incompletely lined with mesoderm. Both pseudocoelom and a true coelom serve as shock absorber and provide space wherein the internal organs can be placed. The fluid present in them sere as medium for transport of nutrients, gases, etc.
Answer:
Stresses such as lack of nutrients, space, competition and water availability.
Explanation:
Lack of nutrients, space, competition and water availability are the stresses that the bryophyte can experience by living on land. The morphological or physiological features such as lowering transpiration rate by stomata, attain specialized structures to collect sunlight and fulfill water requirement by absorbing water from the air if no water is available in the soil etc are the features that the plant has to attain to cope with these stresses.
Correct options A) None
Autosomal dominate refers to alleles harbored by any chromosome other than the sexual pair that show complete dominance over the recessive ones.
The dwarf male father with normal height is homozygous recessive for achondroplasia. The male of heterozygous for the character because this is autosomal dominant. He is also normal vision reason he is X-NY.
The women is color blind and normal height. The cross is X-NYAa x XnX naa. The father will produced gametes x-NA,X-Na , YA and Ya and the mother only gamete X-na. So the son of this type of couple is X-nYAa which can be color blind and dwarf and normal height.
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The answer is C the ancient photosynthetic prokayotes evolved into modern chloroplasts.
(1) All the genotypes are as follows: AABB, AaBB, AABb, AaBb, aaBB, aaBb, AAbb, Aabb, aabb.
(2) Assuming that Aa is dominant and Bb is recessive, there will be 9 phenotypes with both A and B allele dominant (i.e. AaBb, AABb); there will be 3 phenotypes with just the A allele dominant (i.e. Aabb, AAbb); there will be 3 phenotypes with just the B allele dominant (i.e. aaBb, aaBB); and there will be 1 phenotype with both alleles recessive (i.e. aabb). The phenotypic ratio in this case is 9:3:3:1.
(3) The probability of producing an offspring with the aabb genotype is 1/16 or 6%.