Answer:
The final temperature is 348.024°C.
Explanation:
Given data:
Specific heat of copper = 0.385 j/g.°C
Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)
Mass of copper = 62.0 g
Initial temperature T1 = 26.7°C
Final temperature T2 = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
Q = m.c. ΔT
7670 J = 62.0 g × 0.385 j/g °C ×( T2- 26.7 °C
)
7670 J = 23.87 j.°C ×( T2- 26.7 °C
)
7670 J / 23.87 j/°C = T2- 26.7 °C
T2- 26.7 °C = 321.324°C
T2 = 321.324°C + 26.7 °C
T2 = 348.024°C
The final temperature is 348.024°C.
In case of heptane (C7H16) the following structural isomers are possible
shown in figure
a. 1-sec-butylpropane : this is actually 3-methyl hexane
b. 4-methylhexane : this is actually 3-methylhexane
c. 2-ethylpentane : this is actually 3-methyl hexane
d. 1-ethyl-1-methylbutane: 3-methylhexane
e. 3-methylhexane: correct IUPAC
f. 4-ethylpentane: This is actually 3-methylhexane
Hence all represent single isomer
Answer: Option D.
Mechanical and chemical digestion occur in the mouth but only chemical digestion occur in the stomach.
Explanation:
Digestion is the breakdown of larger food particles into smaller ones that can be absorb by the body and pass out the waste product or undigested food. There are two methods digestion occurs in the body and they are; mechanical and chemical digestion.
Mechanical digestion is the physical breakdown of food into smaller pieces. It begins in the mouth when food are chewed.
Chemical digestion involves the breakdown of food into nutrients. This begin in the mouth when food is mixed with saliva and it continue in the stomach where enzymes act on the food.
2 rate constant and 3 mass difference
Answer:
2.0 × 10² g
Explanation:
Step 1: Write the balanced equation
2 NO₂ + 0.5 O₂ ⇒ N₂O₅
Step 2: Calculate the theoretical yield, in moles, of N₂O₅
The molar ratio of NO₂ to N₂O₅ is 2:1.
6.0 mol NO₂ × 1 mol N₂O₅/2 mol NO₂ = 3.0 mol N₂O₅
Step 3: Calculate the theoretical yield, in grams, of N₂O₅
The molar mass of N₂O₅ is 108.01 g/mol.
3.0 mol × 108.01 g/mol = 3.2 × 10² g
Step 4: Calculate the real yield, in grams, of N₂O₅
real yield = theoretical yield × percent yield
real yield = 3.2 × 10² g × 61.1% = 2.0 × 10² g