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tensa zangetsu [6.8K]
2 years ago
10

Which of the following statements is true?

Chemistry
1 answer:
Fittoniya [83]2 years ago
8 0

Answer:

Es la tercera por qué cuando el material varía va cambiando de estado

Explanation:

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the quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dis
Basile [38]

Answer:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

Explanation:

At a redox equation, one substance is being oxidized (losing electrons), and the other is being reduced (gaining electrons). In the given reaction:

BrO₃⁻(aq) + Sb³⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq)

When it's at an acidic solution, it must be ions H⁺ on the reactant, which will form water with the oxygen, so the complete reaction is:

BrO₃⁻(aq) + Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq) + H₂O(l)

As we can see, the antimony is being oxidized (go from +3 to +5), and the Bromo is being reduced. The oxidation number of brome in the reactant, knowing that the oxidation number of O is -2, is:

x + 3*(-2) = -1

x = +5

So, it's going from +5 to -1, and the half-reactions are:

BrO₃⁻(aq) + 6e⁻ → Br⁻(aq)

Sb³⁺(aq) → Sb⁵⁺(aq) + 2e⁻

The number of electrons must be the same, so the second equation must be multiplied by 3:

3Sb³⁺(aq) → 3Sb⁵⁺(aq) + 6e⁻

Thus, the equation will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + H₂O(l)

Now, we verify the amount of the elements, which must be equal on both sides. So, we multiply H₂O by 3, and H⁺ by 6, and the balanced reaction will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

6 0
3 years ago
Achemist is studying an unknown substance and could break the substance into its elemental components only by using
Arturiano [62]
Pure substance




Lmk if its right
8 0
2 years ago
Assuming that seawater is a 3.50 mass % aqueous solution of NaCl, what is the molality of seawater?
Fantom [35]

Hey there!

Consider 100 g of solution:

Mass of NaCl = 3.50% of mass of seawater

( 3.50 / 100 ) * 100 => 3.50 g

Number of moles as shown below:

Molar mass NaCl = 58.44 g/mol

n = Mass / molar mass

n = 3.50 / 58.44 => 0.059 moles of NaCl

Mass of sweater:

Mass of solution -  Mass of NaCl

100 -  3.50 = 96.5 g

96.5 g in Kg :

96.5 / 1000 => 0.0965 Kg

Therefore ,calculate molality  by using  the  following formula:

molality =  number of moles  of solute / mass of solution

molality = 0.059 / 0.0965

molality = 0.61 m


Hope That helps!

7 0
3 years ago
In order to make 0.500 L of a 0.475 M solution, you will need to weigh out how many grams of sucrose (MM = 342 g/mol)?
elixir [45]

The first step to solve this problem is to multiply the volume of solution times its concentration to find the number of moles needed, remember that M=mol/L:

0.500L\cdot\frac{0.475mol}{L}=0.2375mol

Now, use the molar mass of sucrose to find the number of grams needed to make the solution. This is, multiply the number of moles needed times the molar mass:

0.2375mol\cdot\frac{342g}{mol}=81.225g

It means that to make 0.500L of a 0.475M you will have to weigh 81.225g of sucrose.

4 0
1 year ago
Name the alkene with the formula ch3chch2. ethene propene 1-propene 2-propene
Kipish [7]
CH₃-CH=CH₂   propene
-----------------------------------
8 0
3 years ago
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