Answer:
The table tennis balls represent neutrons that are released when the nucleus splits and cause other nuclei to split
Explanation:
Nuclear fission is defined as the separation of a nucleus into two smaller nuclei.
It takes a neutron to set off a nuclear fission reaction. When that occurs, neutrons are released and those neutrons in turn are what set off other nuclear fissions. This is defined as a Nuclear Fission Chain Reaction. In the model, the one tennis ball that will be thrown will be modeled as the starting neutron that sets of the initial (first) fission. The mouse traps with tennis balls represent the other nucleuses waiting to be struck by the one tennis ball. Once the initial tennis ball strikes the first mouse trap, that mouse trap will release its tennis ball hitting others and continuing the cycle.
It can also be modeled as such:
Answer:
A ground wire helps those positive charges get to the ground in a safe, direct and controlled way, where they can be discharged without the risk of electrical shock or fire. Shock Absorber Excess electrical charges are common in any home.
Explanation:
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Answer:
There are 3 steps of this problem.
Explanation:
Step 1.
Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.
Step 2.
Enthalpy of saturated liquid Haq = 781.124 J/g
Enthalpy of saturated vapour Hvap = 2779.7 J/g
Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g
Step 3.
In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy
So, H1=H2
H2= (1-x)Haq+XHvap.........1
Putting the values in 1
2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}
= 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)
1904.976 (J/g) = x1998.576 (J/g)
x = 1904.976 (J/g)/1998.576 (J/g)
x = 0.953
So, the quality of the wet steam is 0.953
Answer:
The pressure inside the flask is 0,09 atm
Explanation:
We calculate the number of moles of O2, we convert the Temperature into unit KELVIN and use the formula of the ideal gases to calculate the pressure:
Weight 1 mol of 02= 15,999g x2= 32g
32g---1mol 02
0,60g---x=(0,60gx1mol O2)/32g= 0,019mol O2
T(K)=273+22=295K
PV=nRT
Px5.0l= 0,019mol x 0,082 lxatm/Kxmolx295 K
P=(0,019mol x 0,082 lxatm/Kxmolx295 K)/5.0l
P=0,09atm
<span>Hazards from huge explosive eruptions comprise extensive ash-falls with small glass particles in it, pyroclastic flows (combinations of hot gases and pumice chunks), and immense lahars which are volcanic mud flows which can even include debris. These put people within the area in danger. Nearby properties get damaged as well within a circumference of tens to hundreds of miles away from the volcano. These eruptions can extensively cause a change to the global climate too. Hazards from quiet eruptions include lava flows which contain exploding fires and creating gas clouds which are rich in chlorine where lava pours into the sea. This can cause damage to wildlife and sea creatures.</span>
