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3 years ago

Describe the transformations of y = x^2 to y = 2(x + 1)^2 - 4

Mathematics

1 answer:

victus00 [196]3 years ago

8 0

Answer:

y=2(x+1)^2-4

Step-by-step explanation:

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A system of equations has infinitely many solutions. If 2y – 4x = 6 is one of the equations, which could be the other equation?

Molodets [167]

Hi there!

$\large\boxed{y = 2x + 6}$

For a system to have infinite solutions, the lines have to be the same. We can begin by rearranging the given equation into the format y = mx + b:

2y - 4x = 6

Move x to the opposite side:

2y = 4x + 6

Divide all terms by 2:

y = 2x + 6

The answer choice that matches this is the first one.

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3 years ago

What is 8.143 * 10 to the 3rd power

Sphinxa [80]

Ten to third power is 1,000 :)

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3 years ago

What is the 10th term of 6,10,14,18?

Tasya [4]

Y = 4x + 2
y = 4×10 + 2
y = 42

the 10th term is 42

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3 years ago

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Which statement is correct about relations and functions?

vitfil [10]

1. all functions are relations.

2.
-7 + 3(-12) ÷ (-3)
-7 - 36 ÷ -3
-7 - (-12)
-7 + 12
5

3.
f(n) = n² - n f(-4)
f(-4) = -4² - (-4)
f(-4) = 16 - (-4)
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hope this helped, God bless!

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3 years ago

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

7 0

3 years ago