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Eduardwww [97]
3 years ago
11

Please help I have to turn this in by the end of the night

Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

is the answer 984???

Step-by-step explanation:

srry if this wrong im not the smartest person in the world

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On the first month test Keiko answered 19 out of 25 questions correctly. On the second test she got 17 out of 20 correct. On whi
LekaFEV [45]

He/she idk, got a higher score on the second test. How you do it is divide the score by the number out of it so like 19 divided by 25. Umm for the ratio, I'm not really sure, I guess you just do 19:25 and 17:20

8 0
3 years ago
Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
HELP ME I DOMT UNDERSTAND
Vilka [71]
1) -30 meters because descend means decrease

2) 20 meters because above means positive

3) 0 because it does not change

Hope this helps!
3 0
3 years ago
Consider the following position function. Find (a) the velocity and the speed of the object and (b) the acceleration of the obje
emmainna [20.7K]

Answer:

Step-by-step explanation:

Given that the position vector of a moving body at time t is

r(t) = (3t ^6,6t - 5,2 + 3t), t\geq 0

Velocity is the derivative of acceleration

v(t) = (18t^5, 6, 3), t positive

Speed would be the magnitude of the velocity and will not have direction

Speed = \sqrt{324t^{10}+36+9 } \\=\sqrt{324t^{10}+45)

Acceleration of the object

a(t) = derivative of velocity of vector

= (90t^4, 0,0)

i.e. acceleration would be in the direction of x axis alone.

5 0
3 years ago
find the number of terms in an AP given that its first and last terms are 13 and - 23 respectively and that its common differenc
Leokris [45]

Answer:

<u>There are 17 terms in the sequence</u>

Step-by-step explanation:

<u>Arithmetic Sequence </u>

An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

a_n=a_1+(n-1)r

Where an is the nth term, a1 is the first term, and r is the common difference.

In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:

\displaystyle n=1+\frac{a_n-a_1}{r}

We need to express r as an improper or proper fraction:

\displaystyle r=-2\frac{1}{4}=-2-\frac{1}{4}=-\frac{9}{4}

Substituting:

\displaystyle n=1+\frac{-23-13}{-\frac{9}{4}}

\displaystyle n=1+\frac{-36}{-\frac{9}{4}}

\displaystyle n=1+36*\frac{4}{9}=17

n=17

There are 17 terms in the sequence

5 0
3 years ago
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