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Arisa [49]
3 years ago
5

Nadia is asked to find a number such that the difference between five times the number and three less than twice the number is e

qual to eighteen. Her work and answer are shown below. 5n−(3−2n)5n−3+2n7n−37nn=====181818213 Is Nadia correct? If not, identify and correct her error.
Mathematics
2 answers:
kolbaska11 [484]3 years ago
6 0

Answer:

Nadia is incorrect, please check explanations for the correction to her work

Step-by-step explanation:

Here, we want to validate the wok of Nadia

Let the number be n

5 times the number is 5 * n = 5n

Difference between 5n and 3 less than twice the number

3 less than twice the number is 2n-3

So it should be 2n-3 ;

The solution is thus;

5n - (2n-3) = 18

5n - 2n + 3 = 18

3n + 3 = 18

3n = 18-3

3n = 15

n = 15/3

n = 5

Nataliya [291]3 years ago
4 0

Answer:

Nadia is incorrect; she did not translate the given information into an equation properly. The first equation should be 5n−(2n−3)=18.

Step-by-step explanation:

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