Ask question

Ask question

All categories

3 years ago

10

Two balls, one twice as massive as the other, are dropped from the roof of a building (freefall). Just before hitting the ground

, the more massive ball has ______ the kinetic energy of the less massive ball. (Neglect air friction.)

1 answer:

Katena32 [7]3 years ago

6 0

KE= 1/2 mv^2

Kinetic Energy is equal to 1/2 x mass x velocity squared

The mass of the larger ball has TWICE
the kinetic energy. KE is directly proportional to the mass.

You might be interested in

What is variable velocity?

KIM [24]

Answer:

velocity in which the space described varies from instant to instant, either increasing or decreasing in the former case called accelerated velocity

Explanation:

I hope this helps :)...

7 0

2 years ago

Read 2 more answers

A physics teacher performing an outdoor demonstration suddenly falls from rest off a high cliff and simultaneously shouts help.

GrogVix [38]

Answer:

$H = 532 m$

Explanation:

When teacher falls into the cliff then she shout for Help at the same time

so here we know that sound will go down and reflect back up

so here in 3 s distance traveled by the sound

$d = vt$

$d = 340 \times 3$

$d = 1020 m$

now in the same time the distance that teacher will fall down is given as

$d_1 = \frac{1}{2}gt^2$

$d_1 = \frac{1}{2}(9.81)(3^2)$

$d_1 = 44.1 m$

now total distance traveled by teacher and sound in 3 s

$d_{total} = d + d_1$

$d_{total} = 1020 + 44.1$

this total distance must be equal to twice the height of the cliff

$2H = 1064.1 m$

$H = 532 m$

7 0

3 years ago

Read 2 more answers

Projectile's horizontal range on level ground is R=v20sin2θ/g. At what launch angle or angles will the projectile land at half o

seraphim [82]

Answer:

$\theta = 15^o \: or\: 75^o$

Explanation:

As we know that the formula of range is given as

$R = \frac{v^2sin2\theta}{g}$

now we know that

maximum value of the range of the projectile is given as

$R_{max} = \frac{v^2}{g}$

now we need to find such angles for which the range is half the maximum value

so we will have

$\frac{R}{2} = \frac{v^2}{2g} = \frac{v^2sin(2\theta)}{g}$

$sin(2\theta) = \frac{1}{2}$

$2\theta = 30 or 150$

$\theta = 15^o \: or\: 75^o$

7 0

3 years ago

A mass m = 14 kg is pulled along a horizontal floor with NO friction for a distance d =5.7 m. Then the mass is pulled up an incl

frosja888 [35]

Answer:

W ≅ 292.97 J

Explanation:

1)What is the work done by tension before the block goes up the incline? (On the horizontal surface.)

Workdone by the tension before the block goes up the incline on the horizontal surface can be calculated using the expression;

W = (Fcosθ)d

Given that:

Tension of the force = 62 N

angle of incline θ = 34°

distance d =5.7 m.

Then;

W = 62 × cos(34) × 5.7

W = 353.4 cos(34)

W = 353.4 × 0.8290

W = 292.9686 J

W ≅ 292.97 J

Hence, the work done by tension before the block goes up the incline = 292.97 J

8 0

3 years ago

Three identical resistors have an equivalent resistance 15.6 ohm when they are connected in series. What is the resistance for e

attashe74 [19]

Answer:

$R=5.2\ \Omega$

Explanation:

In series combination, the equivalent resistance is given by :

$R_{eq}=R_1+R_2+R_3+...$

Let the identical resistors be R. We have, $R_{eq}=15.6\ \Omega$

So,

$R+R+R=15.6\\\\3R=15.6\\\\R=\dfrac{15.6}{3}\\\\R=5.2\ \Omega$

So, the resistance of each resistor is $5.2\ \Omega$ .

4 0

2 years ago