A spring is stretched 2.0 cm. If the same spring is stretched 8.0 cm the ratio of the second and first potential energies of the
spring is
16
9
4
1
1 answer:
Potential energy of spring equals K times X squared divided by 2 where X is displacement
4 times squared equals 16
choose 1st answer
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Answer:
we need more info
Explanation:
Explanation:
- non uniform motion
- F=ma, 1=m(1), m=1Kg
Answer:
15N
Explanation:
F=ma
m=1500g = 1.5kg
a=10m/s2
1.5×10=15 N
I believe the answer is x
|---20----|
| |
| 50 |50
|---D--->|
Start End
Total displacement(D) 20 yards (East).
