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Dmitry_Shevchenko [17]
3 years ago
7

Which term describes an observable fact, event, or circumstance?

Physics
1 answer:
madam [21]3 years ago
3 0

Answer:

Phenomenon

Explanation:

phe·nom·e·non

/fəˈnäməˌnän/

noun

1.

a fact or situation that is observed to exist or happen, especially one whose cause or explanation is in question:

"glaciers are unique and interesting natural phenomena"

synonyms

occurrence, event, happening, fact, situation, etc.

2.

a remarkable person, thing, or event:

"the band was a pop phenomenon just for their sales figures alone"

synonyms

marvel, sensation, wonder, prodigy, miracle, etc.

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Yea it’s called the Saffir-Simpson Hurricane scale, made in 1960s and further developed in 1970s
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3 years ago
A car moving 12m east, then 20m west . What is the displacement?
Ludmilka [50]

Answer:

8 m west

Explanation:

If we say east is the +x direction, and west is the -x direction, then the displacement is:

Δx = 12 m + (-20 m)

Δx = -8 m

8 0
3 years ago
A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 385 kV. The secondary of
enot [183]

Answer:

a) In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new output is 86% of the old output

c) The losses in the new line are 74% the losses in the old line.

Explanation:

a) To relate the turns of primary and secondary to the ratio of voltage we have this expression:

\frac{n_1}{n_2}=\frac{V_1}{V_2}

In the old transformer the ratio of voltages was:

\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{385} =0.03117\\\\n_2=n_1/0.03117=32.1n_1

In the new transformer the ratio of voltages is:

\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{500} =0.024\\\\n_2=n_1/0.24=41.7n_1

In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new current ratio is

\frac{V_1}{V_2}=\frac{I_2}{I_1}=\frac{12}{500}= 0.024\\\\I_2=0.024I_1

If the old current output was 425 kV, the ratio of current was:

\frac{V_1}{V_2}=\frac{I_2}{I_1}=\frac{12}{425}= 0.028\\\\I_2=0.028I_1

Then, the ratio of the new output over the old output is:

\frac{I_{2new}}{I_{2old}} =\frac{0.024\cdot I_1}{0.028\cdot I_1}= 0.86

The new output is 86% of the old output (smaller output currents lower the losses on the transmission line).

c) The power loss is expressed as:

P_L=I^2\cdot R

Then, the ratio of losses is (R is constant for both power losses):

\frac{P_n}{P_o} =\frac{I_n^2R}{I_o^2R} =(\frac{I_n}{I_o} )^2=0.86^2=0.74

The losses in the new line are 74% the losses in the old line.

7 0
2 years ago
Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has
dmitriy555 [2]

Answer:

Explanation:

Given

Wavelength of radiation \lambda =784\ m

We know Energy of wave with wavelength \lambda is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

c=velocity of light

\lambda=wavelength of wave

E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}

E=2.53\times 10^{-28}\ J

Hence the energy of the wave with wavelength 784 m is 2.53\times 10^{-28}\ J

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3 years ago
The moon continues to orbit Earth in an example of the law of conservation of
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A gravity and or D angular momentum

7 0
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Read 2 more answers
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