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3 years ago

Mirrors produce images by doing which of the following to light?

Physics

1 answer:

Gemiola [76]3 years ago

4 0

Answer: C

Reflection

Explanation: Light travels in a straight line. Reflection is one of the properties of light. And this is the property in which mirror make use of. The ability of light to bounce back. It's this bouncing back characteristics of light ray that eventually produce the image of an object by the mirror.

If the light ray is absorbed, no image will be produced.

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Honeybees acquire a charge while flying due to friction with the air. A 100 mg bee with a charge of +23 pC experiences an electr

Sedbober [7]

Answer:

(A) ratio of electric force to weight will be $23.469\times 10^{-10}$

(b) Electric field will be $E=4.26\times 10^{10}N/C$

Explanation:

We have given mass of bee = 100 mg = $m=100\times 10^{-3}=0.1kg$

Charge on bee $q=23pC=23\times 10^{-12}C$

Electric field E = 100 N/C

Weight of the bee $W=mg=0.1\times 9.8=0.98N$

Electric force on the bee $F=qE=23\times 10^{-12}\times 100=23\times 10^{-10}N$

So the ratio of electric force on the bee and weight is $=\frac{F}{W}=\frac{23\times 10^{-10}}{0.98}=23.469\times 10^{-10}$

(B) To hold the bee in air electric force must be equal to weight of bee

So $mg=qE$

$0.1\times 9.8=23\times 10^{-12}E$

$E=4.26\times 10^{10}N/C$

4 0

2 years ago

What is the volume of the cone?

dezoksy [38]

Answer:

42.417 cm³

Explanation:

The formula to find the volume of a cone is :

V = $\frac{1}{3}$ × π r² h

Here,

r ⇒ radius ⇒ 3 cm

h ⇒ height ⇒ 4.5 cm

V = $\frac{1}{3}$ × π r² h

V = $\frac{1}{3}$ × π × 3 × 3 × 4.5

V = $\frac{1}{3}$ × π × 9 × 4.5

V = $\frac{1}{3}$ × π × 40.5

V = $\frac{1}{3}$ × 3.142 × 40.5

V = $\frac{1}{3}$ × 127.251

V = <u>42.417 cm³</u>

4 0

2 years ago

Water has a ph of 7. ph is defined as the negative log of the hydrogen ion concentration [h ]. explain why water is assigned a p

AfilCa [17]

Answer: Concentration of H+ =10^-7; log of 10^-7=7 so pH=7

Explanation:

4 0

1 year ago

A solid sphere of mass 4.0 kg and radius 0.12 m starts from rest at the top of a ramp inclined 15°, and rolls to the bottom. The

cluponka [151]

Answer:

v = 4.1 m/s

Explanation:

As per mechanical energy conservation law we can say that initial total gravitational potential energy of the sphere is equal to final kinetic energy of rolling

so we will say

$mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2$