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Juli2301 [7.4K]

3 years ago

5

Match the glacier feature with its description.

2 answers:

Roman55 [17]3 years ago

6 0

Answer:

kettles: holes left by glaciers.

cirques: three-sided valleys

erratics: large, out-of-place rocks bouldersleft by glaciers.

drumlins: egg-shaped hills

Explanation:

scZoUnD [109]3 years ago

5 0

Answer:

kettles: holes left by glaciers.

cirques: three-sided valleys

erratics: large, out-of-place rocks bouldersleft by glaciers.

drumlins: egg-shaped hills

Explanation: APEX

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The amplitude $A_{2}$ is 8.307 m

When describing the peak value of a quantity, such as the level of sound waves or the power and voltage in electrical and electronic systems, the term amplitude is employed. A louder sound has a bigger amplitude, and a softer sound has a smaller amplitude.

As we previously discussed in the concept session, the square root of the water's speed is inversely related to the amplitude of its waves.

$A\alpha\frac{1}{\sqrt{v} }$

Solve for first case:

$A_{1}=\frac{1}{\sqrt{v_{1} } }$

Solve for second case:

$A_{2}=\frac{1}{\sqrt{v_{2} } }$

So, the two equations is equal

$A^{2} _{1} v_{1} = A^{2} _{2} v_{2}$

$=A^{2} _{2} \sqrt{g d_{2} }$

Rearrange and solve for the amplitude $A_{2}$ :

$A_{2} =\sqrt{\frac{A^{2}_{1} v_{1} }{v_{2} } }$

$=\sqrt{\frac{A^{2}_{1} v_{1} }{\sqrt{g d_{2} } } }$

$=\sqrt{\frac{(1.8m)^{2} X200 m/s }{\sqrt{9.8m/s^{2}X9 m } } }$

= 8.307 m

So, The amplitude $A_{2}$ is 8.307 m.

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A pendulum of 50 cm long consists of small ball of 2kg starts swinging down from height of 45cm at rest. the ball swings down an

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Assuming that all energy of the small ball is transferred to the bigger ball upon impact, then we can say that:

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