Answer: 
, 
and 
are formed at the end of the reaction. They are named as tin (IV) oxide or stannic oxide, nitrogen dioxide and water respectively.
Explanation: Reaction of tin and nitric acid is given as:
Three products are formed at the end of the reaction which are:
- which is termed as stannic oxide or Tin (IV) oxide. This is a white colored solid.
- which is termed as nitrogen dioxide. These are brown colored fumes.
- which is termed as water.
At the starting tin was a silvery-white colored solid and after the reaction, it changed the color to milky-white. This change in color is due to the chemical reaction happening between tin and nitric acid.
Release of brown fumes are also an indication that a chemical reaction has taken place.
Answer:
2.67 g/mL
Explanation:
Initial Volume of water = 10.0 mL
Final Volume pf water = 15.46 mL
Mass = 14.74g
Density = Mass / Volume of aluminium
Volume of aluminium = Final Volume of water - Initial Volume of water = 15.46 - 10 = 5.46mL
Density = 14.74 / 5.46 = 2.67 g/mL
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams
therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams
Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
- A chemical reaction is considered as a process of transformation of chemical reactants into products.
- Chemical reactions involve change in position of electrons or breaking the bonds between atoms to form new molecules. (no change in the elements present).
- Chemical reactions are best described by chemical equations
So the correct answer is B
