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lisov135 [29]
3 years ago
5

=" \sqrt{5 + 2 \div \sqrt{5 - 2} } " alt=" \sqrt{5 + 2 \div \sqrt{5 - 2} } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Artemon [7]3 years ago
6 0

Answer:

so yea what was the answer again

Step-by-step explanation:

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Round 5,836,197 to the nearest humdred
Olenka [21]
5,836,200 Is the answer :) Have a Great day!!!
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3 years ago
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Write an equation in slope-intercept form of the line that passes through (-5, 19) and (5.13).
ruslelena [56]

Answer:

y=-3/5x+16

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(13-19)/(5-(-5))

m=-6/(5+5)

m=-6/10

simplify

m=-3/5

y-y1=m(x-x1)

y-19=-3/5(x-(-5))

y-19=-3/5(x+5)

y=-3/5x-15/5+19

y=-3/5x-3+19

y=-3/5x+16

3 0
3 years ago
tina baught 3 video games that each cost the same amount that tax on each vido game was 1.29 she paid
crimeas [40]

Answer:

x=21.5

Step-by-step explanation:

I had this question and got it right!

6 0
3 years ago
If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?
Dennis_Churaev [7]

The value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

Given that trigonometric ratio:

tan\theta = \frac{11}{60}

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to \theta = 11

Adjacent side to \theta = 60

So, cot \theta =\frac{AdjacentSide }{OppositeSide}

cot\theta =\frac{60}{11}

Therefore, the value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

To get more about trigonometric ratios visit:

brainly.com/question/24349828

6 0
2 years ago
Isaac is 3 years older than Rachael. In 4 years the sum of their ages will be 75. How old is Isaac now?
MatroZZZ [7]

Answer:

36 years old

Step-by-step explanation:

let x = age of Rachael

2x+3 = current ages combined

[(2x+3)+4]+4 = 75

2x+11 = 75

2x = 75-11

2x = 64

x = 32

Rachel is 32 years old. Isaac is 3 years older, which is 35 years old.

Hope this helped! If you need any help, tell me in the comments.

6 0
3 years ago
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