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-Dominant- [34]
3 years ago
13

2Al +6HCl → 2AlCl3 + 3H2 then solve the problem below. Find the number of moles of Al used to produce 2.5 moles of H2

Chemistry
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

2.5 moles of H2 will be produced by \frac{5}{3} moles of Al

Explanation:

The given equation is  a balanced equation

2Al +6HCl → 2AlCl3 + 3H2

As per this reaction, 2 moles of Al are used to produce 3 moles of H2

1 mole of H2 will be produced by \frac{2}{3} moles of Al

2.5 moles of H2 will be produced by \frac{2}{3} * 2.5 = \frac{5}{3} moles of Al

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Sloan [31]

Answer:

The  change in entropy in the system is -231.5 J/K

Explanation:

Step 1: Data given

The normal boiling point of ethanol (C2H5OH) is 78.3 °C = 351.45 K

The molar enthalpy of vaporization of ethanol is 38.56 kJ/mol = 38560 J/mol

Mass of ethanol = 97.2 grams

Pressure = 1 atm

Step 2: Calculate the entropy change of vaporization

The entropy change of vaporization = molar enthalpy of vaporization of ethanol / temperature

The entropy change of vaporization = 38560 J/mol / 351.45 K

The entropy change of vaporization = -109.72 J/k*mol

Step 3: Calculate moles of ethanol

Moles ethanol = mass / molar mass ethanol

Moles ethanol = 97.2 grams / 46.07 g/mol

Moles ethanol = 2.11 moles

Step 4: Calculate  change in entropy

For 1 mol = -109.72 J/K*mol

For 2.11 moles = -231.5 J/K

The  change in entropy in the system is -231.5 J/K

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Which of the following subatomic particles is uncharged?
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I think the given chart is electronegativity chart.

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