The balanced equation for
Ca(OH)2 + H3PO4→ Ca3(PO4)2 + H2O is
3 Ca(OH)2 +2 H3PO4→ Ca3(Po4)2 + 6 H2O
3 moles of Ca(OH)2 reacted with 2 moles of H3PO4 to form 1 mole of Ca3(PO4)2 and 6 moles of H2O
Answer:
a)decanting,filtering,and evaporating.
Answer:
103.6°C
Explanation:
We solve this problem, with the Ideal Gases Law. We know that moles of gas are not changed through time.
P . V = n . R . T
So n (number of moles) and R (Ideal Gases constant) are the same, they are cancelled. In the two different states, we can propose:
P₁ . V₁ / T₁ = P₂ . V₂ /T₂
We need to make some conversions:
100 mL . 1 L/ 1000mL = 0.1L
500 kpa . 1atm / 101.3 kPa = 4.93 atm
300°C + 273 = 573 K
We replace data:
4.93 atm . 10L / T₂ = 750 atm . 0.1L / 573K
4.93 atm . 10L = (750 atm . 0.1L / 573K) . T₂
(4.93 atm . 10L) / (750 atm . 0.1L / 573K) → T₂
T₂ = 376.65 K
We convert K to °C → 376.65 K - 273 = 103.6 °C
To solve this we use the
equation,
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the
volume of the stock solution, M2 is the concentration of the new solution and
V2 is its volume.
We prepare the solution by measuring 25 mL of the stock solution in a graduated cylinder or by using a pipette. Then, put the stock solution in a 100mL of volumetric flask. Dilute it by adding distilled water up to the 100mL mark in the flask. It should be noted that the lower meniscus of the solution should be the point where you observe the volume.
Answer:
The answer to this is
The velocity of the 27.3Kg marble after collision is = 16.24 cm/s
Explanation:
To solve the question, let us list out the given variables and their values
Mass of first marble m1 = 27.3g
Velocity of the first marble v1 = 21.0 cm/s
Mass of second marble m2 = 11.7g
Velocity of the second marble v2 = 12.6 cm/s
After collision va1 = unknown and va2 = 23.7 cm/s
From Newton's second law of motion, force = rate of change of momentum produced
Hence m1v1 + m2v2 = m1va1 + m2va2 or
va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s
The velocity of the 27.3Kg marble after collision is = 16.24 cm/s
