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Misha Larkins [42]
3 years ago
11

Five identical keys are suspended from a balance, which is held horizontally as shown. The two keys on the left are attached to

the balance 6 cm from the pivot and the three keys on the right are attached 5 cm from the pivot. What will happen when the person lets go of the balance beam?
Engineering
1 answer:
Ann [662]3 years ago
6 0

Answer:

movement in clockwise direction.

Explanation:

The following parameters or information are given from the question above, they are:

[1]. There are two identical keys, [2]. two out of the five keys are attached to 6cm from the pivot, [3]. three keys out of the five keys on the right are attached 5 cm.

Therefore, considering the moment of force, the two keys on the left = 2 × 6 = 12.

Also, considering the moment of force, the 3 keys on the right = 3 × 5 = 15.

Therefore, we have more weight on the right keys. So, in order to balance the force there must be movement in clockwise direction.

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likoan [24]

Answer:

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Explanation:

The power dissipated in each branch is ...

  P = V^2/R

So, the branch powers are ...

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Total power is ...

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Nancy ate a 500 Cal lunch. Neglecting efficiency issues (i.e., assuming 100% conversion of energy to work), to what height could
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Answer:

4265.04\ \text{m}

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Explanation:

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g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Potential energy of food is given by

PE=mgh\\\Rightarrow h=\dfrac{PE}{mg}\\\Rightarrow h=\dfrac{2.092\times 10^6}{50\times 9.81}\\\Rightarrow h=4265.04\ \text{m}

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Energy of H_2 = \dfrac{30\times10^9}{1000}=30\times 10^6\ \text{J/kg}

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The power requirement is 2.38\times 10^{10}\ \text{W}.

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Explanation:

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