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KatRina [158]
2 years ago
13

You are to design the control for an automatic candy vending machine. The candy bars inside the machine cost 25 cents, and the m

achine accepts nickels, dimes, and quarters only. The inputs to the control are a set of three signals that indicate what kind of coin has been deposited, as well as a reset signal. The control should generate an output signal that causes the candy to be delivered whenever the amount of money received is 25 cents or more no change is given . Once the candy has been delivered, some external circuitry will generate a reset signal to put the control back into its initial state.
Required:
a. Identify your inputs and outputs, and draw the ASM chart that implements this finite state machine.
b. Assuming no change given, draw a state diagram that implements the finite state machine.
c. Implement the finite state machine using D, T and JK flip-flops. You may use gray code state assignment.
d. Verify the D flip-flop implementation in (b).
e. Write Verilog HDL models for the machine based on the state diagram in (a) and the D flip-flop sequential circuit that you implement in (b).
f. Modify your control design such that the vending machine may give change if more than 25 cents is deposited. You do not have to implement your design. State diagram is sufficient.
Engineering
1 answer:
labwork [276]2 years ago
6 0

Answer:

I believe that it is E. Write Verilog HDL models for the machine based on the state diagram in (a) and the D flip-flop sequential circuit that you implement in (b).

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You are working in a lab where RC circuits are used to delay the initiation of a process. One particular experiment involves an
Ymorist [56]

Answer:

t'_{1\2} = 6.6 sec

Explanation:

the half life of the given circuit is given by

t_{1\2} =\tau ln2

where [/tex]\tau = RC[/tex]

t_{1\2} = RCln2

Given t_{1\2} = 3 sec

resistance in the circuit is 40 ohm and to extend the half cycle we added new resister of 48 ohm. the net resitance is 40+48 = 88 ohms

now the new half life is

t'_{1\2} =R'Cln2

Divide equation 2 by 1

\frac{t'_{1\2}}{t_{1\2}} = \frac{R'Cln2}{RCln2} = \frac{R'}{R}

t'_{1\2} = t'_{1\2}\frac{R'}{R}

putting all value we get new half life

t'_{1\2} = 3 * \frac{88}{40}  = 6.6 sec

t'_{1\2} = 6.6 sec

7 0
3 years ago
Disconnecting a circuit while in operation can create a voltage blank
zlopas [31]

Answer:

what is the question

Explanation:

confused

5 0
3 years ago
2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk
BabaBlast [244]

The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

  • 9874

Speed,

  • 1567 kph

Pressure,

  • 122 kPa

The temperature will be:

→ T = 15.04-[0.00649(9874)]

→     = 15.04-64.082

→     = -49.042^{\circ} C

now,

→ P_o = 101.29[\frac{(-49.042+273.1)}{288.08} ]^{(5.256)}

→      = 27.074

hence,

→ The pressure differential will be:

= 122-27

= 95 \ kPa

Thus the above solution is correct.

Learn more about pressure difference here:

brainly.com/question/15732832

3 0
2 years ago
Select the right answer<br>​
Kruka [31]

Answer:

for 1st question the answer is 5th option.

for 2nd question the answer is 2nd option

hope it helps you mate

please mark me as brainliast

5 0
3 years ago
HELP<br><br><br>the overall width of a part is dimensioned as 3.00 ± 0.02. what is the tolerance
MariettaO [177]

Answer:

Not knowing the units the tolerance is 0.02.  I would presume mm but hopefully your question has more detail.  

Explanation:

The tolerance is the portion after the main dimension (+/- 0.02).  In our case we have bilateral tolerance since there is tolerance in both directions (positive and negative).  If you were building a part the acceptable range would be 2.98 to 3.02 based on the tolerance provided.  

3 0
3 years ago
Read 2 more answers
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