The volume of 0.160 m Li2S solution required to completely react with 130 ml of 0.160 CO(NO3)2 is calculated as below
write the reacting equation
Co(NO3)2 + Li2S = 2LiNO3 + COS
find the moles of CO(NO3)2 = molarity x volume
= 130 ml x 0.160=20.8 moles
since the reacting moles between CO(NO3)2 to LiS is 1:1 the moles of LiS is also 20.8 moles
volume of Lis is therefore = moles of Lis/ molarity of LiS
= 20.8/0.160 = 130 Ml
Explanation:
Molarity is defined as number of moles of solute in liter of solution.
Whereas number of moles is equal to mass of given substance divided bu its molar mass.
Since molar mass of HCl is 36.46 g/mol. Therefore, calculate the number of moles of HCl as follows.
![Number of moles of HCl = \frac{mass of given}{Molar mass of HCl}](https://tex.z-dn.net/?f=Number%20of%20moles%20of%20HCl%20%3D%20%5Cfrac%7Bmass%20of%20given%7D%7BMolar%20mass%20of%20HCl%7D)
= ![\frac{25 g}{36.46 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B25%20g%7D%7B36.46%20g%2Fmol%7D)
= 0.686 mol
Hence, molarity of solution will be as follows.
Molarity = ![\frac{no. of moles}{volume of solution}](https://tex.z-dn.net/?f=%5Cfrac%7Bno.%20of%20moles%7D%7Bvolume%20of%20solution%7D)
= ![\frac{0.686 mol}{0.15 L}](https://tex.z-dn.net/?f=%5Cfrac%7B0.686%20mol%7D%7B0.15%20L%7D)
= 4.573 mol/L
Thus, we can conclude that molarity of a solution that contains 25 g of HCl in 150 mL of solution is 4.573 mol/L.
• The bond that exist between the CCl4 compound ,forms a covalent bond ,, this can be illustrated in the diagram below:
• We can see that it contains four non-polar covalent bond between carbon and chloride