What is the molarity of a solution that contains 25 g of HCl in 150 mL of solution? (The molar mass of HCl is 36.46 g/mol.)
2 answers:
Explanation:
Molarity is defined as number of moles of solute in liter of solution.
Whereas number of moles is equal to mass of given substance divided bu its molar mass.
Since molar mass of HCl is 36.46 g/mol. Therefore, calculate the number of moles of HCl as follows.
=
= 0.686 mol
Hence, molarity of solution will be as follows.
Molarity =
=
= 4.573 mol/L
Thus, we can conclude that molarity of a solution that contains 25 g of HCl in 150 mL of solution is 4.573 mol/L.
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Answer:
Explanation:
A covalent bond involves the sharing of electrons to make the atoms more stable, and so they satisfy the Octet Rule (8 valence electrons).
Typically each atom contributes an electron to form an electron pair. This is a single bond. There are also double bonds (two pairs of electrons), triple bonds (three pairs of electrons), and coordinate covalent bonds.
Sometimes, to satisfy the Octet Rule and achieve stability, one atom contributes both of the electrons in an electron pair. This is different from other covalent bonds because usually each of the 2 atoms contributes an electron to make a pair.
Answer:
59.8%
Explanation:
First find the Mr of manganese (III) nitrate.
Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = <u>240.9</u>
Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:
Mr of (O₃)₃ = (16 × 3) × 3 = <u>144</u>
Now we can find percentage composition / percentage by mass of oxygen.
% composition = × 100
% composition = × 100 = <u>59.776%</u>
∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).