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3 years ago

What is the molarity of a solution that contains 25 g of HCl in 150 mL of solution? (The molar mass of HCl is 36.46 g/mol.)

Chemistry

2 answers:

lawyer [7]3 years ago

7 0

Explanation:

Molarity is defined as number of moles of solute in liter of solution.

Whereas number of moles is equal to mass of given substance divided bu its molar mass.

Since molar mass of HCl is 36.46 g/mol. Therefore, calculate the number of moles of HCl as follows.

$Number of moles of HCl = \frac{mass of given}{Molar mass of HCl}$

= $\frac{25 g}{36.46 g/mol}$

= 0.686 mol

Hence, molarity of solution will be as follows.

Molarity = $\frac{no. of moles}{volume of solution}$

= $\frac{0.686 mol}{0.15 L}$

= 4.573 mol/L

Thus, we can conclude that molarity of a solution that contains 25 g of HCl in 150 mL of solution is 4.573 mol/L.

Tomtit [17]3 years ago

5 0

Answer:moles

Explanation:

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Graham's law states that the rate of diffusion or effusion of a given gas is inversely proportional to the square root of its molar mass.

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Rate1/rate2 = sqrt(MW2/MW1)

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b) The new equilibrium concentrations after reestablishment of the equilibrium :

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Explanation:

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of $SbCl_5$ is increasing .So, the equilibrium will shift in the right direction.