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3 years ago

How does the air on a hot day compare with the air on a cold day?

1 answer:

7 0

Air on a hot day translates to hot air and air on a cold day translates to cold air. The hot air usually have more energy due to particles being more excited by the heat.

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Jane is sliding down a slide. What kind of motion is she demonstrating?

Alex Ar [27]

Im pretty sure it would be kinetic <span />

8 0

4 years ago

Ferrous sulfate (FeSO4) was used in the

BARSIC [14]

Ferrous sulfate (FeSO4) is obtained by the reaction of aqueous ferric sulfate with gaseous sulfur dioxide and water according to the equation below:

Aqueous ferric sulfate = $Fe_2(SO_4)_3_{(aq)}$

Gaseous sulfur dioxide = $SO_2_{(g)}$

Water = $H_2O_{(l)}$

Aqueous sulfuric acid = $H_2SO_4_{ (aq)}$

Aqueous ferrous sulfate = $FeSO_4_{ (aq)}$

Thus, the balance equation becomes:

$Fe_2(SO_4)_3_{(aq)}$ + $SO_2_{(g)}$ + $2H_2O_{(l)}$ $--->$ $2 H_2SO_4_{ (aq)} + 2 FeSO_4_{ (aq)}$

More on ferrous sulfate can be found here: brainly.com/question/10834028

6 0

3 years ago

which term is used when sugar is completely dissolved in water

GaryK [48]

The term which is used is homogeneous.
when sugar is completely dissolved in the water, the mixture or solution homogeneous, both in same phase and same uniform texture that is liquid.
There two types of mixtures are heterogeneous and homogeneous in different phases.
If sugar is not completely dissolved in water and you see the crystals of sugar in water, then the solution will be heterogeneous.

3 0

4 years ago

The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approxi

Novay_Z [31]

Answer:

1.115 g

Explanation:

Applying,

R = R' $2^{n/t}$ ................... Equation 1

Where R = original sample of radon-222, R' = sample of radon-222 left after decay, n = Total time, t = half-life.

make R' the subject of the equation

R' = R/( $2^{n/t}$ )............... Equation 2

From the question,

Given: R = 73.9 g, n = 23 days, t = 3.8 days.

Substitute these values into equation 2

R' = 73.9/( $2^{23/3.8}$ )

R' = 73.9/ $2^{6.05}$

R' = 1.115 g

6 0

3 years ago

Which statement must be true for any chemical reaction at equilibrium?

sergejj [24]

<span>The correct answer is 3. The concentration of the product and the concentration of the reactants are equal. That is because matter cannot be created or destroyed and the product cannot randomly become something else in the reaction, nor can a reactant change into something different. Simply put, you cannot turn things like water into gold because there will always be an equilibrium.</span>

4 0

4 years ago

Read 2 more answers