Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
The balanced equation for reaction of chlorine gas with fluorine gas is written as follows
Cl2(g) + 3 F2(g) = 2ClF3(g)
chlorine react with flourine to form CIF3 . The phases of reactant and product is the gas phase
Answer:
Explanation:
The formula of calcium nitride is Ca₃P₂.
The masses of each element are:
So, there are 61.94 g of P in 182.18 g of Ca₃P₂.
In 500 g of Ca₃P₂:
There are 
in 500.0 g of Ca₃P₂.
