Answer:
The answer to your question is <u>111 g of CaCl₂</u>
Explanation:
Reaction
2HCl + CaCO₃ ⇒ CaCl₂ + CO₂ + H₂O
Process
1.- Calculate the molecular mass of Calcium carbonate and calcium chloride
CaCO₃ = (1 x 40) + (1 x 12) + ((16 x 3) = 100 g
CaCl₂ = (1 x 40) + (35.5 x 2) = 111 g
2.- Calculate the amount of calcium chloride produced using proportions.
The proportion CaCO₃ to CaCl₂ is 1 : 1.
100 g of CaCO₃ ------------- 111 g of CaCl₂
Then 111g of CaCl₂ will be produced.
Answer: the statement that is wrong about uncouplers is option A ( they allow ATP synthesis with no electron transport).
Explanation:
An uncoupler is a molecule that disrupts oxidative phosphorylation by dissociating the reactions of ATP synthesis from the electron transport chain. They allow electron transport without ATP synthesis. Their mechanism of action is basically to transport protons back into the matrix, preventing the required buildup of charge on the other side.
2,4-DNP is an example of an uncoupler.
Reaction of Copper with Mercuric Nitrate is as follow,
Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg
According to equation,
1 Mole of Cu reacts to form = 1 Mole of Hg
So,
1.20 Moles of Cu will react to produce = X Moles of Hg
Solving for X,
X = (1.20 mol × 1 mol) ÷ 1 mol
X = 1.20 mol of Hg
Result:
1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
Answer:
389 mL solution
Explanation:
Step 1: Given data
- Concentration of the NaCl solution: 0.900% (m/v)
- Mass of sodium chloride: 3.50 g
- Volume of saline solution: ?
Step 2: Calculate the volume of saline solution
The concentration of the NaCl solution is 0.900% (m/v), that is, there are 0.900 g of NaCl every 100 mL of solution.
3.50 g NaCl × 100 mL solution/0.900 g NaCl = 389 mL solution
