Answer
The senders PC is using UDP protocol
Explanation
UDP is the User Datagram Protocol which is used as an alternative communication protocol to the TCP which is used primarily for establishing low latency and loss of tolerating connections between applications on the internet UDP is normally used by the programs running on different computers on a network. Its purposes is to send short messages which are datagrams. It is not much reliable because of its occasional loss of packet. Due to this packet loss the recipient is not guaranteed that the data being streamed will not get interrupted. This is because If a router on the Internet starts getting overloaded, or a packet gets corrupted due to interference or anything, the packet will be dropped unlike the TCP (Transmission control protocol)which resend the packets and keeps re sending. The UDP does not resend the packets which are dropped. Once they are dropped that all.
<h3>What is a Finite automata?</h3>
A finite state machine (FSM) or finite state automaton (FSA), or simply a state machine, is a mathematical model of computation. It is an abstract machine that can be in exactly one of a finite number of states at any given time. The FSM may change from one state to another in response to some input; the change from one state to another is called a transition. An FSM is defined by a list of its states, its initial state, and the inputs that trigger each transition. Finite-state machines are of two types - deterministic finite-state machines and non-deterministic finite-state machines. A deterministic finite-state machine can be constructed equivalent to any non-deterministic machine.
With that being said, the DFA is equivalent to the expression 10(0+11)0*1 The expression that you've specified requires at least three 1 to be accepted. Breaking it down into parts.
<h3>Writting the automata:</h3>
<em>S0: 1 => S1 ; 1 </em>
<em>S0: 0 => error ; 0 </em>
<em>S1: 0 => S1 ; 10+ </em>
<em>S1: 0 => S2 ; 10(0 </em>
<em>S2: 0 => S2 </em>
<em>S2: 1 => S3 </em>
<em>S3: 1 => S4 </em>
<em>S4: 0 => S4 </em>
<em>S4: 1 => S5 </em>
<em>S5: 1 => S6 (final state) </em>
See more about automata at brainly.com/question/14937298
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Answer:
The quicksort pivot is an arbitrary element within the collection that is being sorted. Using the pivot point, the collection of elements is partitioned into two smaller lists of elements. Using some logic, the smaller elements are placed left of the pivot point, and larger elements are placed to the right of the pivot point. Ideally, you would prefer you pivot point to be a median of your dataset to optimize the creation of the two sublists into a balanced state.
Cheers.
Answer:
do{
cout<<"Introduce number \n"; //print the message
cin>>num; //set the value of the number given
}while(num<1 || num>10); //repeat while the number is out of the range
cout<<"Number: "<<num; //print the number
Explanation:
The idea behind this code is to create a loop in which I can compare the number given (between 1 and 10) and then print the number or get back and ask the number again.
#include <iostream>
using namespace std;
int main()
{
int num; //create num variable
do
{
cout<<"Introduce number \n"; //print the message
cin>>num; //set the value of the number given
}while(num<1 || num>10); //repeat while the number is out of the range
cout<<"Number: "<<num; //print the number
}
