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Jobisdone [24]
3 years ago
12

A cylinder has the following dimensions: radius = 3.7 cm and height = 6.5 cm. If the mass of the cylinder is 40.67 g, calculate

the density in g/cm'. (V = trh) Cylinder​
Chemistry
1 answer:
katrin [286]3 years ago
8 0

Answer:

49.8cm

Explanation:

hope it helps i even double checked for you :D

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The element nickel has the following properties. Select the two that are chemical properties of nickel.
kkurt [141]
<span>a. It melts at 1455oC I know this is correct I need One more</span>
5 0
4 years ago
The cell theory states that all living things are composed of one or more cells that carry out the functions needed to support l
saw5 [17]

Answer:

New cells arise from existing cells.

Explanation:

According to the cell theory, "all living things are composed of one or more cells; the cell is the basic unit of life; and new cells arise from existing cells"(Lumen Learning).

Cells are the basic unit of life. Some organisms consists of only one cell while other organisms have many cells and are called multicellular organisms.

In multicellular organisms, new cells are formed by the division of preexisting cells.

7 0
3 years ago
Atoms of which two elements have a combined total of 23 protons?
Alik [6]

Answer:

A

Explanation:

Sodium has 11 electrons and Magnesium has 12 electrons. Since here you need to consider atoms, they must have equal amount of protons as electrons to be considered neutral, and so an atom.

So simply 11+12 =23

6 0
3 years ago
How much heat, in calories, is needed to raise the temperature of 125.0 g of Lead (c lead = 0.130 J/g°C) from 17.5°C to 41.1°C?
pav-90 [236]
95.6 cal
are needed.
Explanation:
Use the following equation:
q
=
m
c
Δ
T
,
where:
q
is heat energy,
m
is mass,
c
is specific heat capacity, and
Δ
T
is the change in temperature.
Δ
T
=
T
final
−
T
initial
Known
m
=
125 g
c
Pb
=
0.130
J
g
⋅
∘
C
T
initial
=
17.5
∘
C
T
final
=
42.1
∘
C
Δ
T
=
42.1
∘
C
−
17.5
∘
C
=
24.6
∘
C
Unknown
q
Solution
Plug the known values into the equation and solve.
q
=
(
125
g
)
×
(
0.130
J
g
⋅
∘
C
)
×
(
24.6
∘
C
)
=
400. J

(rounded to three significant figures)
Convert Joules to calories
1 J
=
0.2389 cal
to four significant figures.
400
.
J
×
0.2389
cal
1
J
=
95.6 cal

(rounded to three significant figures)
95.6 cal
are needed.
8 0
3 years ago
How many moles are in 3.90 x1030 atoms of Zn?
zaharov [31]
Explanation:
The problem basically wants you to find a way to convert between the number of atoms present in the sample and the number of moles they are equivalent to.
To convert between atoms and moles we use something called Avogadro's constant, which basically acts as the definition of a mole.
More specifically, in order to have one mole of an element you need
6.022 x 10^23 atoms of that element. You can thus use this number as a conversion factor to take you from atoms to moles or vice versa.
In your case, you will have


3.90 x 10^ 26 atoms Zn x 1 mole Zn ( Avogrado’s constant) / 6.022 x 10^23 atoms Zn

= 6.5 x 10^8 is the answer
7 0
3 years ago
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