Question

Katie is making a strawberry milkshake in her blender. A 0.05kg strawberry is rapidly spun around the inside of the container with a speed of 11.0 m/s, held by a centripetal force of 12.0 N. What is the radius of the blender at the strawberry’s location? Round answers to two decimal places.

Answer 1

Answer:

The radius of the blender is approximately 0.5041$\bar 6$ meters

Explanation:

The given parameters are;

The mass of the strawberry, m = 0.05 kg

The speed with which the strawberry is spun, v = 11.0 m/s

The centripetal force holding the strawberry = 12.0 N

The formula for the centripetal force, $F_c$, is given as follows;

$F_c = \dfrac{m \cdot v^2}{r}$

Where;

r = The radius of the centripetal rotation, which is the radius of the blender

$\therefore r = \dfrac{m \cdot v^2}{F_c}$

Substituting the values gives;

$\therefore r = \dfrac{0.05 \times 11^2}{12} = \dfrac{121}{240} \approx 0.5041 \bar 6$

The radius of the blender, r ≈ 0.5041$\bar 6$ meters.