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2 years ago

Please help me please and thank you.

Mathematics

1 answer:

Lelechka [254]2 years ago

4 0

A: If you plug in the x and y values the inequalities are true

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What is the value of x? Show work.

ella [17]

Answer:

x=5

Step-by-step explanation:

This is because the inscribed angle of the circle or angle EFG is equal to the twice of the degree of the arc EG. Therefore, we can create this equation:

12+40=2(8x+10)

12+40=16x+20

20=4x

x=5

5 0

3 years ago

(x^3)^9 = A: x^12 B: x^27 C: x^3 D: x^6

Grace [21]

$(x^3)^9=x^{27}$

3 0

3 years ago

What is the unit price of cheese if 1.6 pounds cost $14.40?

Nookie1986 [14]

Answer:

$8.87 per pound

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

the length of a rectangle is 2 times in width if the perimeter of the rectangle is 36 in find its length and width

Basile [38]

Answer:

Length=12 inches Width=6 inches

Step-by-step explanation:

X can stand for the width. 2x can stand for the length since it is twice the width. The perimeter would then equal 6x. 6x is equal to 36. Divide by 6 to isolate x. X equals 6 inches. So twice the width would be 12 inches.

8 0

2 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

e) $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

2 years ago