Part A:What percentage of the total students surveyed like both watching television and reading?
The total amount of student is 230
The amount of students that like to read and watch television is 80
As a fraction it is 80/230
Turn that to a percentage
It is:34.7826%
Part A=34.7826%
Part B:What is the probability that a student does not like watching television also does not like reading?
On the table it shows 20
So the probability is 20/230
Part B=20/230
Answer:
D. 20
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Geometry</u>
- All angles in a triangle add up to 180°
Step-by-step explanation:
<u>Step 1: Set Up Equation</u>
3x + 3x + 10 + 2x + 10 = 180
<u>Step 2: Solve for </u><em><u>x</u></em>
- Combine like terms: 8x + 20 = 180
- Isolate <em>x</em> term: 8x = 160
- Isolate <em>x</em>: x = 20
2*20+2*15= 70 This is the perimeter
20*15=300 This is the area.
Hope this helps :)
The desmos link is in the reply section below...
1.) y = 1.56x + 1.29
2.) the slope is 1.56
As the weeks are increasing, the student's balance is growing about 1.56 per week.
3.) y = 24.69
4.) 50 = 1.56x + 1.29
50 - 1.29 = 1.56x + 1.29 - 1.29
48.71 =1.56x
48.71 / 1.56
31.2
Answer:
The solution set is (5,6).
Step-by-step explanation:
Given equations are:
-6x + 6y= 6 Eqn 1
-6x + 3y=-12 Eqn 2
Subtracting Eqn 2 from Eqn 1
(-6x+6y)-(-6x+3y)= 6-(-12)
-6x+6y+6x-3y=6+12
3y = 18
Dividing both sides by 3

Putting y=6 in Eqn 1
-6x+6(6)=6
-6x+36=6
-6x=6-36
-6x=-30

Hence,
The solution set is (5,6).