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e-lub [12.9K]
3 years ago
11

Which of the h values are solutions to the following equation? h^2=.36

Mathematics
1 answer:
Maru [420]3 years ago
3 0

Answer:

h=0.6, -0.6

Step-by-step explanation:

take the root of both sides and solve

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XZW XYV find the perimeter of XZW? <br><br> PLS HELP
sdas [7]

9514 1404 393

Answer:

  180 units

Step-by-step explanation:

The perimeter of ∆XYV is ...

  Pxyv = XY +YV +VX

  Pxyv = 29 +31 +40 = 100

The triangles are similar, so the scale factor from ∆XYV to ∆XZW applies to the perimeter. That scale factor is ...

  WX/VX = (32+40)/40 = 1.8

Then ...

  Pxzw = 1.8 × Pxyv = 1.8 × 100

  Pxzw = 180 . . . units

8 0
3 years ago
P=(a+b) solve for a<br><br>How to solve a from this formulaa
Bezzdna [24]


Watch me closely:

You said that              <u>P = a + b</u>

Subtract ' b ' from each side:        P - b  =  a

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4 years ago
Solve for x and then type the answer. Just type the number. If there are 2 answers, then type both numbers, separated by a comma
Basile [38]
(x + 2)^(1/3) = 3 equivalent to ∛[(x+2)] = 3

Raise both sides to exponent 3


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3 0
3 years ago
George takes a photograph of a rectangular window that is 312 feet tall and 134 feet wide. He prints the photograph on paper so
Snowcat [4.5K]

Answer:

A':A = 1742:7

Step-by-step explanation:

Applying,

A' = L'W'............... Equation 1

Where A' = Area of the window, L' = Length of the window, W' = Width of the window.

From the question,

Given: L' = 312 ft, W' = 134 ft

A' = (312×134)

A' = 41808 ft²

Similarly,

A = LW.................. Equation 2

Where A = Area of the image of the window, L and W is thw length and width of the image of the window

Given: L = 12 ft, W = 14 ft

Therefore,

A = 12×14

A = 168 ft²

Therefore the ratio of A' to A = 41808:168 = 1742:7

A':A = 1742:7

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3 years ago
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