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Elena-2011 [213]
3 years ago
11

Will give brainliest to correct answer.

Mathematics
2 answers:
o-na [289]3 years ago
7 0
Use Pythagorean's Theorem to solve for c.  c^2=(2 \sqrt{x^2+3x})^2+(3)^2.  We will simplify the right side by squaring both terms.  c^2=4(x^2+3x)+9  which simplifies even further to  c^2=4x^2+12x+9.  In that polynomial, the leading coefficient, 4, is a perfect square, and so is the constant at the end, 9.  So that polynomial is the sum of perfect squares.  It will break down like this:  c^2=(2x+3)^2  so then taking the square root of both sides gives us that c = 2x + 3, choice on the top right.
Anna71 [15]3 years ago
7 0
The correct answer would be C=2x+3
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A bus ride for a senior citizen cost $1.25. A monthly pass costs $35.
Bond [772]

Answer:

25 or more

Step-by-step explanation:

30/1.is 24 so it would be 25 or more times for it to be a better deal

7 0
3 years ago
Please help me out please
natita [175]

Answer:

RC = 40

Step-by-step explanation:

Note that the circumcentre is equally distant from the triangle's 3 vertices.

That is : PC = RC = QC

Equate any pair and solve for x

Using RC = PC, then

5x - 15 = 3x + 7 ( subtract 3x from both sides )

2x - 15 = 7 ( add 15 to both sides )

2x = 22 ( divide both sides by 2 )

x = 11

Hence

RC = (5 × 11) - 15 = 55 - 15 = 40 units

5 0
3 years ago
The answers and how to solve them
Gwar [14]
A.30x+1 that's all I got
7 0
3 years ago
Evaluate the expression if y=4.4 and z= 12<br> z2+ 8y
Evgen [1.6K]

Answer: <em>59.2</em>

Step-by-step explanation:

<em>Take your equation</em>

<em>z2+8y</em>

<em>Now plug in the values given</em>

<em>(12)2+8(4.4)</em>

<em>24+35.2</em>

<em>59.2</em>

5 0
3 years ago
Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

And that is the answer.
6 0
3 years ago
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