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frosja888 [35]
2 years ago
9

Which of the following can be calculated from the mass of the reactants used in a chemical reaction?

Chemistry
2 answers:
borishaifa [10]2 years ago
6 0

Answer:

Three of these are correct.

Explanation:

Amount of limiting reactant used in a reaction

Theoretical yield of products

Amount of excess reactant from a reaction

Readme [11.4K]2 years ago
5 0

Answer:

points.

Explanation:

yeah........

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PLZ HELP, GIVING BRAINLIEST!!
Veseljchak [2.6K]

Answer:

2.29 moles of Cr₂O₃ are produced

Explanation:

This is the reaction:

4 Cr + 3O₂ → 2Cr₂O₃

Ratio for this equation is 4:2, so 4 moles of chromium can produce the half of moles of chromium(III) oxide

4.58 mol of Cr may produce (4.58  .2)/4 = 2.29 moles of Cr₂O₃

4 0
3 years ago
What is the formula mass of MgO (how much does one mole of it weigh)
Nadusha1986 [10]

Answer:

40.3044 g/mol

Explanation:

hope this helps

4 0
2 years ago
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While dinner was cooking, Rachel noticed that there was steam coming from a pot of boiling water. Which of the following stateme
Alex777 [14]

Answer:

There is a physical change as the water is evaporating, producing a gas.

7 0
2 years ago
If two atoms of sodium (Na) combine with one molecule of chlorine (cI2), which of the following could be the product?
enyata [817]
2Na + Cl2 ----> 2NaCl 
  .: product have to be " 2NaCl "  
 
7 0
3 years ago
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Según la Organización Mundial de la Salud, el nitrato de plata ( densidad = 4.35 g/cc ) es una sustancia con propiedades cáustic
OlgaM077 [116]

Answer:

737.52 mL de agua

Explanation:

En este caso solo debes usar la expresión de molaridad de una solución la cual es:

M = moles / V

Donde:

V: Volumen de solución.

Como queremos saber la cantidad de agua, queremos saber en otras palabras cual es la cantidad de solvente que se utilizó para preparar los 800 mL de disolución.

Una disolución se prepara con un soluto y solvente. El soluto lo tenemos, que es el nitrato de plata. Con la expresión de arriba, calculamos los moles de soluto, y luego su masa. Posteriormente, calculamos el volumen con la densidad, y finalmente podremos calcular el solvente de esta forma:

V ste = Vsol - Vsto

Primero calcularemos los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con estos moles, se calcula la masa usando el peso molecular reportado que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Ahora usando el valor de la densidad, calcularemos el volumen de soluto empleado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Finalmente, la cantidad de agua necesaria es:

V agua = 800 - 62.48

V agua = 737.52 mL

8 0
3 years ago
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