Explanation:
The dipoles in CO are in opposite directions so they cancel each other out, although CO₂ has polar bonds, it is a nonpolar molecule. Therefore, the only intermolecular forces are London dispersion forces. Water (H2O) has hydrogen bond present which is a polar bond which has a high intermolecular force.
Water which has high intermolecular force will require more energy that is a higher temperature to overcome these attractions and are pulled together tightly to form a solid at higher temperatures, so their freezing point is higher.
As the temperature of a liquid decreases, the average kinetic energy of the molecules decreases and they move more slowly.
CO with lower intermolecular forces will not solidify until the temperature is lowered further.
From the reaction of ammonia and sulfuric acid in aqueous solution
2nh3(aq)+h2so4(aq)<span>→</span> (NH4)2SO4 + H2O
will be formed.Sulfuric acid is diprotic so is able to give up 2 H+ ions.
It is an acid-base neutralisation reaction forming ammonium sulphate as the salt.
2NH3 with H2SO4 reacts in a neutralization reaction to form salt water, with ammonium sulphate left behind to crystallize after evaporation.
For this specific problem, these would be the answer to the
following choices:
a. excited
b. ground
c. impossible
I am hoping that these answers have satisfied your queries and
it will be able to help you, thank you and have a nice day.
Answer:
Sodium Carbonate
Explanation:
Washing Soda�Sodium Carbonate (Na2CO3) (Na = Sodium, water softening)
Sodium softens water by binding with Calcium and Magnesium forming solid, which can be rinsed off the fabric. �However, if not rinsed thoroughly, the minerals can redeposit onto the fabric and cause problems. �
The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
<h3>
Position of 18o-labeled methanol in the products</h3>
The 18O label will appear at position b in the product as indicated in the image.
This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).
While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.
Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
Learn more about methanol here: brainly.com/question/17048792
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