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4 years ago

What are the 5 types of chemical reactions?

1 answer:

7 0

Combination or Synthesis Reaction. A combination of synthesis reaction is one. where a new product is synthesized by combination of two or three reactants.

Decomposition Reaction

Displacement or Replacement Reaction

Acid Base Reaction

Combustion Reaction

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What are the two ways we can get the mass of an object?

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Explanation:

divide the objects weight by the acceleration of gravity to find the mass

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4 years ago

How is it possible for light to change genetic material?

Ivanshal [37]

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When light hits CRY2, it changes shape and binds to its natural partner protein, known as CIB1. When light shines on the cells, the CRY2 protein binds to CIB1, which is floating in the cell. CIB1 brings along a gene activator, which initiates transcription, or the copying of DNA into mRNA.

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3 years ago

Question 6 (1 point)

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This statement would be best characterized by the law of conservation of momentum—choice C.

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3 years ago

The reactants in a chemical reaction contain 900 J of chemical energy. The products of the reaction contain 9000 J of chemical e

natta225 [31]

For the reaction to take place the energy of the reactants must reach to the energy level of the products:
we have 900 J in the reactants and 9000 J for the products so the reactants need 8100 J to reach to the value of energy of products (900 + 8100 = 9000)
So the correct answer is C. <span>The reaction absorbs 8100 J of energy from the surroundings as it proceeds. </span>

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4 years ago

Read 2 more answers

Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at

ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and $O_2$ .

$\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

$4Al+3O_2\rightarrow 2Al_2O_3$

From the balanced reaction we conclude that

As, 3 mole of $O_2$ react with 4 mole of $Al$

So, 0.188 moles of $O_2$ react with $\frac{4}{3}\times 0.188=0.251$ moles of $Al$

From this we conclude that, $Al$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Al_2O_3$

From the reaction, we conclude that

As, 3 mole of $O_2$ react to give 2 mole of $Al_2O_3$

So, 0.188 moles of $O_2$ react to give $\frac{2}{3}\times 0.188=0.125$ moles of $Al_2O_3$

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of $Al_2O_3$ releases amount of heat = 1676 kJ

So, 0.125 mole of $Al_2O_3$ releases amount of heat = $0.125\times 1676kJ=209.5kJ$

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0

3 years ago