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2 years ago

Find the value of x. 105° (10x – 5)

Mathematics

1 answer:

Katarina [22]2 years ago

5 0

Answer:

525o • (2x - 1)

Step-by-step explanation:

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Write two equivalent expressions to represent the area of this rectangle.

KengaRu [80]

Answer:

The two expression to represent area is (5 x - 10) sq. units or 5( x- 2) sq. units

Step-by-step explanation:

Here, the length of the rectangle = (x-2) units

The width of the rectangle = 5 units

Now, AREA OF A RECTANGLE = LENGTH x WIDTH

So, here AREA = 5 ( x- 2)

= (5 x - 10) sq. units

( as by Distributive property: A (B-C) = AB - AC)

Hence, the two expression to represent area is (5 x - 10) sq. units or 5( x- 2) sq. units

6 0

3 years ago

Please help me with this question

Margarita [4]

The correct answer is "The next fraction in the pattern is 342/324" because the denominator and numerator are being multiplied by three everytime.

7 0

3 years ago

What is the slope of the line?

Liula [17]

The slope is the gradient

Gradient = rise/run
Gradient = -1/1
Gradient = -1
Slope = -1

7 0

3 years ago

Read 2 more answers

Which of the following equations is of a parabola with a vertex at (1, -2)?

arlik [135]

The general eaquation of a parabola in terms of its vertex is:

y = a(x - h)^2 + k

where the vertex point is (h, k)

therefore, an equation of a parabola with vertex (1, -2) is:

y = 5(x - 1)^2 - 2

8 0

3 years ago

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball traveled 79 met

Sav [38]

Answer:

0.395 kilometre

Step-by-step explanation:

Given:

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.

On his second stroke, the ball traveled 79 meters and went into the hole.

Question asked:

How many kilometres from the hole was Martin when he started?

Solution:

Let distance from Martin starting point to the hole in meters = $x$

On Martin's first stroke, ball traveled = $\frac{4}{5} \ of \ total \ distance\ to\ the\ hole$

$=\frac{4}{5} \times x=\frac{4x}{5}$

On his second stroke, the ball traveled and went to the hole = 79 meters

Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

$x=\frac{4x}{5} +79\\ \\ Subtracting\ both\ sides\ by \ \frac{4x}{5}\\ \\ x- \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5}+79\\ \\ \frac{5x-4x}{5} =79\\ \\ By \ cross\ multiplication\\ \\ x=79\times5\\ \\ x=395\ meters$

Now, convert it into kilometre:

1000 meter = 1 km

1 meter = $\frac{1}{1000}$

395 meters = $\frac{1}{1000}\times395=0.395\ kilometre$

Thus, there are 0.395 kilometre distance from Martin starting point to the hole.

8 0

3 years ago