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Aloiza [94]
3 years ago
10

Mr. And Mrs ikan deposited $15,000 into college savings accounts with an annual compound interest rate 5.25% when their daughter

was born. If the money remains in the saving account until she is 18 , what will be the total amount in the account ?
Mathematics
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

$37,650

Step-by-step explanation:

A=15000(1+0.0525)^18

A=15000(2.51)

A=37650

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What number is 37 1/2% of 32?
Serggg [28]
37.5% of 32 is 12

if you move the decimal point in the percentage 2 places to the left you will get a number you can multiply with 

so 0.375 x 32 = 12


6 0
3 years ago
The difference of the product of a number, y, and 3 and 24 is 237. Write an equation
lbvjy [14]

y + 3 +24 = 237

y + 27 = 237

y + 27 - 27 = 237 -27

y = 210

5 0
3 years ago
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
A car dealership pays $8,350 for a car. They mark up the price by 17.4% to get the retail price. What is the retail price of the
tangare [24]
$ 9802.9and it said the answer had to be 20 characters long so i wrote this
3 0
3 years ago
PLEASE HELP!!! BRAINLIEST TO CORRECT COMPLETE ANSWER!
notka56 [123]

Answer:

y=16x+1

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(1,17) and (2,33).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1,17), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1 and y1=17.

Also, let's call the second point you gave, (2,33), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=2 and y2=33.

Now, just plug the numbers into the formula for m above, like this:

m=  

33 - 17/  2 - 1

or...

m=  16/ 1

or...

m=16

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=16x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(1,17). When x of the line is 1, y of the line must be 17.

(2,33). When x of the line is 2, y of the line must be 33.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=16x+b. b is what we want, the 16 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1,17) and (2,33).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(1,17). y=mx+b or 17=16 × 1+b, or solving for b: b=17-(16)(1). b=1.

(2,33). y=mx+b or 33=16 × 2+b, or solving for b: b=33-(16)(2). b=1.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(1,17) and (2,33)  is   y=16x+1

4 0
2 years ago
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