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sineoko [7]
3 years ago
8

PLEASE HELP I need to answer the question quick .

Mathematics
1 answer:
Finger [1]3 years ago
8 0

Answer:

D. y+3 = 6(x-1)

Step-by-step explanation:

i just wrote it out and i think thats the answer but not sure. hopefully this helps :)

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In how many different ways can seven children line up in one row to have their picture taken?
____ [38]
I think it’s 49 cause it’s definitely more than 7 and the other two options seem far too high and unreasonable so it’s most likely 49 :)
6 0
3 years ago
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Which number can be inserted in the parentheses so the numbers are ordered from least to greatest?
leva [86]
We have that
<span>negative 3, left-parenthesis space right-parenthesis, negative 1 and one-eighth 
</span>[-3,(  ),-1,1/8]

we know that
<span>the number to insert must be between -3 and -1------> (-3,-1)
</span>
<span>A. negative 3 and one-half -------> is not in the interval (-3,-1)
B. 0 </span>-------> is not in the interval (-3,-1)<span>
C. negative 2 and one-fourth ----> -2 1/4 belong to the interval (-3,-1) 
D. one and one-half </span> -------> is not in the interval (-3,-1)


therefore 
the answer is the option
C. negative 2 and one-fourth 
8 0
3 years ago
Read 2 more answers
Judy worked 8 hours and Ben worked 10 hours. Their combined pay was 80. when judy worked 9 hours and Ben worked 5 hours, their c
saul85 [17]

Answer:

Judy 80+65 = $145/17 hrs = $8.53

Ben 80 +65 = $145/15 Hrs = $9.33

Step-by-step explanation:


6 0
3 years ago
1
Mariana [72]

Answer:

x = 6

Step-by-step explanation:

∠ DBC + ∠ ABC = ∠ ABD , substitute values

5x - 4 + 8x - 3 = 79

13x + 1 = 79 ( subtract 1 from both sides )

13x = 78 ( divide both sides by 13 )

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8 0
3 years ago
JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

5 0
2 years ago
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