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Verizon [17]
3 years ago
7

In ⊙H, Arc I K ≅ Arc J K, mArc I K = (11x + 2)°, and mArc J K = (12x – 7)°.

Mathematics
2 answers:
Bumek [7]3 years ago
7 0

Answer:

202

Step-by-step explanation:

Did it on Edu.

Ronch [10]3 years ago
4 0

Answer:

The answer is 202.

Step-by-step explanation:

You might be interested in
1.688 × 10⁴ = write in standard format​
Neporo4naja [7]

Answer

16880

Step-by-step explanation:

10x10x10x10=10,000

1.688x10,000=16880

hope that helps

7 0
3 years ago
Read 2 more answers
WILL GIVE BRAILIST TO PERSON WHO ANSWERS CORRECTLY!!
den301095 [7]

Answer:

The Answer is 16

Step-by-step explanation:

The three angles enclosed in a triangle, made by its sides, are called its internal angles. The sum of internal angles of a triangle is

180

o

. Based on its internal angles, a triangle can be classified as acute angled, right angled and obtuse angled.

Your Welcome! :)

6 0
3 years ago
Read 2 more answers
Please please please help look at the picture
olchik [2.2K]

Answer:

132

Step-by-step explanation:

4 0
3 years ago
Emily wants to hang a painting in a gallery. The painting and frame must have an area of 31 square feet. The painting is 5 feet
seropon [69]
Area=legnth times width=31
the frame must go around the frame with equal legnth, x
so
the total area (meaning the frame +picture) is 5+x by 6+x
31=(5+x)(6+x)
expand
31=30+11x+x^2
minus 31 both sides
0=-1+11x+x^2
x^2+11x-1=0

answer is third one
6 0
3 years ago
Read 2 more answers
A procurement specialist has purchased 25 resistors from vendor 1 and 30 resistors from vendor 2. Let
Ulleksa [173]

Answer:

Normal Distribution

Standard error = 0.473

Step-by-step explanation:

We are given the following information:

A procurement specialist has purchased 25 resistors from vendor 1  are assumed to be normally distributed with mean 100 ohms and standard deviation 1.5 ohms.

x_{1,1}, x_{1,2}, ... , x_{1,25}\\\mu_{1} = 100\\\sigma_1 = 1.5

A procurement specialist has purchased 30 resistors from vendor 2 are assumed to be normally distributed with mean 105 ohms and standard deviation 2.0 ohms.

x_{2,1}, x_{2,2}, ... , x_{2,30}\\\mu_{2} = 105\\\sigma_1 = 2.0

The difference of two independent normally distributed random variables is normal, with its mean being equal to the difference of the two means, and its variance being the sum of the two variances.

Thus, the sampling distribution of X_1-X_2 is a normal distribution.

Mean =

100 - 105 = -5

Standard error =

\sqrt{\displaystyle\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}\\\\=\sqrt{\displaystyle\frac{(1.5)^2}{25} + \frac{(2)^2}{30}}\\\\= 0.473

8 0
3 years ago
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