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pickupchik [31]
2 years ago
13

Why are carcinogens difficult for toxicologists to identify

Chemistry
1 answer:
Jet001 [13]2 years ago
4 0

Answer:

Carcinogens are difficult to identify because there may be a long lag time between exposure to the agent and the detectable onset of cancer

Explanation:

quizlet.com/193673418/environmental-chapter-9-flash-cards/

You might be interested in
Law of Universal Gravitation (what factors affect gravity and how?)
olya-2409 [2.1K]

Explanation:

Hey there!

According to the law of gravitation, the factors that affects the gravity are:

  • Mass of the heavenly bodies.
  • Distance from the centre of the body to next body.

Mass of heavenly bodies:<em>The </em><em>ma</em><em>s</em><em>s </em><em>of </em><em>heavenly</em><em> bodies</em><em> </em><em>affect</em><em> </em><em>the </em><em>gravity</em><em>.</em><em> </em><em>We </em><em>know </em><em>that </em><em>gravity</em><em> is</em><em> </em><em>directly</em><em> proportional</em><em> to</em><em> the</em><em> </em><em>mass </em><em>of</em><em> heavenly</em><em> bodies</em><em>.</em><em> </em><em>so,</em><em> </em><em>when </em><em>the </em><em>mass </em><em>is </em><em>more </em><em>there </em><em>is </em><em>more </em><em>gravity </em><em>and </em><em>where</em><em> </em><em>there </em><em>is </em><em>less </em><em>mass </em><em>there </em><em>is </em><em>less </em><em>gravity</em><em>.</em>

Distance from the centre of the body to next body: <em>It </em><em>is</em><em> </em><em>one </em><em>of</em><em> the</em><em> </em><em>factor </em><em>to </em><em>influence</em><em> </em><em>gravity</em><em>.</em><em> </em><em>When </em><em>there </em><em>is</em><em> </em><em>more </em><em>distance</em><em> </em><em>there </em><em>is</em><em> </em><em>less </em><em>gravity</em><em> </em><em>and </em><em>where </em><em>there </em><em>is </em><em>distance</em><em> </em><em>more </em><em>force </em><em>is </em><em>there.</em><em> </em><em>Is </em><em>means </em><em>gravity</em><em> is</em><em> </em><em>inversely</em><em> proportional</em><em> to</em><em> </em><em>the </em><em>distance</em><em> </em><em>between </em><em>the </em><em>bodies</em><em>.</em>

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
2 years ago
The electrical wires in your home use what type of circuits?
Helga [31]
The house wiring should be done parallel because, in parallel connection there will be more advantages than a series connection.

Let a house is wired in series and it contains a fan, tube light, TV, refrigerator. All the devices are connected in series. Now, due to some disturbance the fan speed working or it burned. Then since the connection was a series, due to one appliance failure causes the whole circuit to fail. If it is burned that means it making an open circiut. Then there will be no current flow in the circuit.

Now if it was a parallel connection as we know already, the parallel connection is nothing but individual appliances connected to the same line by tappings. That means there's no dependency of one appliance on another. So if an appliance fail or burns it doesn't effects the remaining appliances. And there will be uninterrupted supply to the healthy appliances can be achieved.

That’s why we use parallel for house wiring
7 0
3 years ago
Read 2 more answers
A more reactive metal displaces a less reactive metal from salt solution. Such reactions are called:
motikmotik

Answer:

Displacement Reaction.

6 0
3 years ago
Read 2 more answers
What is the wavelength of the matter wave associated with an electron (me= 9.1 x 10-31 kg) moving with a speed of 2.5 x 107 m/s?
riadik2000 [5.3K]
And h value is constant 6.624 x 10^-34

3 0
3 years ago
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
natali 33 [55]

Answer:

There are 0.93 g of glucose in 100 mL of the final solution

Explanation:

In the first solution, the concentration of glucose (in g/L) is:

15.5 g / 0.100 L = 155 g/L

Then a 30.0 mL sample of this solution was taken and diluted to 0.500 L.

  • 30.0 mL equals 0.030 L (Because 30.0 mL ÷ 1000 = 0.030 L)

The concentration of the second solution is:

155 \frac{g}{L} *\frac{0.030L}{0.500L}=9.3\frac{g}{L}

So in 1 L of the second solution there are 9.3 g of glucose, in 100 mL (or 0.1 L) there would be:

1 L --------- 9.3 g

0.1 L--------- Xg

Xg = 9.3 g * 0.1 L / 1 L = 0.93 g

8 0
3 years ago
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