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Contact [7]
3 years ago
12

An object resting on a table weighs 100 N. With what force is the object pushing on the table? With what force is the table push

ing on the object? Explain how you got your answer.
Chemistry
1 answer:
Marina86 [1]3 years ago
4 0

<u>Answer:</u> The force that the table is applying on the object will be 100 N.

<u>Explanation:</u>

We are given that ab object is applying a 100 N of force on the resting table and we need to find the force that the table is applying on the object. To find that we will follow Newton's Third Law, which states that:

For every action, there is an equal and opposite reaction.

This law means that for every interaction, two equal forces are acting on both the interacting objects in opposite direction.

Hence, the force that the table is applying on the object will be 100 N.

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A laser used to read CDs emits red light of wavelength 700 nm. How many photons does it emit each second if its power is?(a) 0.1
Elenna [48]

power = work/time

watt = joule/sec

a) power = 0.10 watt = 0.1joules/sec

work = power * time

= 0.10 * 1 =0.1joules

work is northing but energy

therefore energy is 0.1joules

according to planks quantum theory E = nhν where nis the no. of photons ; h is planks constant; ν isfrequency

hence, n = E/hν

or n = Eλ/hc (ν = c/λ)

n = (0.1*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^18photons

b) similar to the above calculation

here E = 1.0joules

n = (1.0*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^17photons

4 0
3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?
castortr0y [4]

Explanation:

I think the correct answer is B

Hope this helped u

8 0
3 years ago
Which of the following describes the arrangement of valence electrons in a bond between H and F?
Sloan [31]
C; The Valence electrons spend more time around the atom of F
6 0
3 years ago
45.7 grams of calcium chloride reacts with an excess of aluminum oxide. How many grams of aluminum chloride will be produced
damaskus [11]
Molar mass (CaCl2) = 40.1 +2*35.5 = 111.1 g/mol
Molar mass (AlCl3) = 27.0 +3*35.5= 133.5 g/ mol

                                               
3CaCl2+Al2O3 -------->3CaO +2AlCl3
mole from reaction              3 mol                                              2 mol
mass from reaction         3mol* 111.1g/mol                             2 mol*133.5g/mol
                                               333.3 g                                            267.0 g
mass from problem              45.7 g                                               x g

Proportion:
  333.3 g  CaCl2  -------   267.0 g AlCl3
  45.7 g   CaCl2   --------   x g    AlCl3

x=45.7*267.0/333.3= 36.6 g AlCl3
5 0
3 years ago
Make sure to show your answer using correct units and sig figs. (all of the
allochka39001 [22]

Answer:

1. 84g.mol`¹

2. 342g.mol`¹

3 0
2 years ago
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