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2 years ago

Need help ASAP!!

Mathematics

2 answers:

Ugo [173]2 years ago

8 0

Answeruse pitaghora theorema

a2+b2=c2

21^2+x^2=29^2

441+x^2=841

x^2=400x=√400=20

any questions?why 3 stars tho

alex41 [277]2 years ago

4 0

Answer: B.

Explanation: That side is shorter than the other known sizes so it can’t be above 20

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Answer:

i think its c. They thought they paid too much in taxes.

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3 years ago

When a number x is multiplied by 9, the result is 35 . What is the value of x?

svp [43]

a number x is multiplied by 9 : 9x

a number x is multiplied by 9, the result is 35 : 9x = 35

solve for x

9x = 35
x = 35/9
x = 3 8/9 (3 and 8/9)

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3 years ago

(06.04 MC)

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$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

◉ $\large\bm{ -4}$

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

Before performing any calculation it's good to recall a few properties of integrals:

$\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx + \int_{a}^bmdx}$

$\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a f(x)dx= \int^c _a f(x)dx+ \int^{b} _c f(x)dx }$

So we apply the first property in the first expression given by the question:

$\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}$

And we solve the second integral:

$\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }$

Then we take the last equation and we subtract 10 from both sides:

$\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 8}$

And we divide both sides by 2:

$\small\longrightarrow \sf{\dfrac{2 { \int}^{3} _{2} }{2} = \dfrac{8}{2} }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}$

Then we apply the second property to this integral:

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}$

Then we use the other equality in the question and we get:

$\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx = 8 + 2 \int ^3_{-2} f(x)dx = 4}$

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}$

We substract 8 from both sides:

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}$

• $\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}$

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1 year ago

A and B are complementary angles. If mA=(x+8)° and mB =(8x+1), find the measure of A

Black_prince [1.1K]

Answer:

$\angle A=17\textdegree$

Step-by-step explanation:

We know that A and B are complementary angles. So, they must add up to 90°. As an equation:

$\angle A+\angle B=90$

Since we know their equations, substitute:

$(x+8)+(8x+1)=90$

Solve for x. Combine like terms on the left:

$9x+9=90$

Subtract 9 from both sides:

$9x=81$

Divide both sides by 9:

$x=9$

So, the value of x is 9.

We want to find A. So, let's use the equation for A:

$\angle A=x+8$

Substitute 9 for x:

$\angle A=9+8$

Add:

$\angle A=17\textdegree$

So, the measure of A is 17°.

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lys-0071 [83]

Answer:

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