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3 years ago

Need help ASAP!!

Mathematics

2 answers:

Ugo [173]3 years ago

8 0

Answeruse pitaghora theorema

a2+b2=c2

21^2+x^2=29^2

441+x^2=841

x^2=400x=√400=20

any questions?why 3 stars tho

alex41 [277]3 years ago

4 0

Answer: B.

Explanation: That side is shorter than the other known sizes so it can’t be above 20

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Write an equation in slope-intercept form for the line that satisfies the following condition. slope 7, and passes through (5, 3

allsm [11]

Y = mx + b
slope(m) = 7
(5,30)...x = 5 and y = 30
now we sub and find b, the y int
30 = 7(5) + b
30 = 35 + b
30 - 35 = b
-5 = b

so ur equation is : y = 7x - 5 <==

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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PLESE HELP ill GIVE BRANILY<br><br> Solve for x. 3.5(7-x)+32=106-1.5(4x+18)

murzikaleks [220]

Answer:

X=9

Step-by-step explanation:

3.5(7−x)+32=106−1.5(4x+18)

Step 1: Simplify both sides of the equation.

3.5(7−x)+32=106−1.5(4x+18)

(3.5)(7)+(3.5)(−x)+32=106+(−1.5)(4x)+(−1.5)(18)(Distribute)

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(−3.5x)+(24.5+32)=(−6x)+(106+−27)(Combine Like Terms)

−3.5x+56.5=−6x+79

Step 2: Add 6x to both sides.

−3.5x+56.5+6x=−6x+79+6x

2.5x+56.5=79

Step 3: Subtract 56.5 from both sides.

2.5x+56.5−56.5=79−56.5

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4 years ago

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John stands 150 meters from a water tower and sights the top at an angle of elevation of 36º. If John's eyes are 2 meters above

horsena [70]

Answer:

The height of tower $DB=111\ meters$ .

Step-by-step explanation:

Diagram of the given scenario is shown below.

Given that,

Distance between John and tower is $CE=150 \ meters$ .

Angle of elevation to the top of the tower is $\angle DEC=36$ °.

Height of John is $CB=2\ meters$ .

To Find: Height of the tower $DB$ .

So,

In triangle ΔDCE,

$Tan$ (∠ $DEC)= \frac{DC}{CE}$

$Tan (36)= \frac{DC}{150}$

$DC= tan(36)\times 150$

$DC=108.98\ meters$

Now,

To calculate the height of tower we have

$DB=DC+CB$

$DB=108.98+2$

$DB=110.98\ meters$ ≈ $111 \ meters$

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3 years ago

What is the answer to. Work out 5-10/-5

CaHeK987 [17]

10/-5 = -2 so 5 - (-2)= 7

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4 years ago