X+y+z=3 x-y+z=2 x+y-z=1
1 answer:
Answer:
Step-by-step explanation:
I'm assuming you are solving this system for x, y, and z. Do it this way:
Combine the first 2 equations and the second 2 equations and eliminate the y's. The first 2 equations:
x + y + z = 3
x - y + z = 2
which solves to
2x + 2z = 5
The second 2 equations:
x - y + z = 2
x + y - z = 1
which solves to
2x = 3 so
x = 3/2 or 1.5
Now sub that x value into the bold equation above to get:
2(1.5) + 2z = 5 and
3 + 2z = 5 and
2z = 2 so
z = 1
Now we plug back in to solve for y:
1.5 + y + 1 = 3 and
2.5 + y = 3 so
y = .5
The solution set then is (1.5, .5, 1) or in fraction form:
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Answer: Choice C
Closed filled in circle at -3; shading to the right.
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Explanation:
Follow the steps shown below to isolate x. Note that the inequality sign flips when we divide both sides by a negative number.
Here's another way to isolate x
The inequality sign flip happens much earlier when we go from the format of to
(in step 3)
The graph of this will have a closed filled in circle at -3, then shading to the right to describe all values -3 or larger.
This is why we go for choice C.