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3 years ago

There are 35 boys in the 6th grade and 42 girls the ratio is 5 boys 7 girls how do I get the answer

1 answer:

6 0

Answer: The ratio is wrong, it's 5 boys 6 girls

Explanation: To find this you would find the LCF (Least Common Factor) which would be 7, and divide both by 7, being 35/7 and 42/7, giving you the answers 5 and 6.

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Solve this rational equation <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Bx%20%2B%204%7D%20%20%3D%20%20%5Cfrac%7B4%7

sergey [27]

Answer:

$x = - 12$

C.E.: x =/= -4

Step-by-step explanation:

$\frac{x}{x + 4} = \frac{4}{x + 4} + 2 \\ \frac{x}{x + 4} = \frac{4 + 2x + 8}{x + 4} \\ x = 4 + 2x + 8 \\ - x = 12 \\ x = - 12$

6 0

3 years ago

What is the sum of interior angles of a convex nonagon

zmey [24]

A nonagon has 9 sides, so n = 9

S = sum of the interior angles
S = 180*(n-2)
S = 180*(9-2)
S = 180*7
S = 1260

Answer is choice B

8 0

3 years ago

Use the graph or table to identify the value that makes this relationship proportional.

julsineya [31]

Answer:

Step-by-step explanation:

Pls vote my answer as brainliest

3 0

3 years ago

Read 3 more answers

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago

Please explain your answer

MariettaO [177]

Answer:

e = -1/2

Step-by-step explanation:

4/3 = -6e - 5/3

transfer -6e to the right

4/3 = -5/3 -6e

Find the LCM of 3,3and 1

and their LCM is 3. So, divide all through by 3

3(4/3) = 3(-5/3) - 6e × 3

4 = -5 -18e

combine

4 + 5 = -18e

9 = -18e

divide by -18

9/ -18 = -18e/ -18

-1/2 = e

e = -1/2

5 0

3 years ago