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IrinaVladis [17]
2 years ago
14

Find the value of x.

Mathematics
1 answer:
grandymaker [24]2 years ago
8 0
I think X is 2. But I am not sure, cuz I don’t know what you teacher is really asking you to do.

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A system has one each of two different types of components in joint operation. Let X and Y denote the random lengths of the live
RSB [31]

Answer:

The value of E(Y/X) is 2.

Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

So the joint density function is given as

f(x,y)=\left \{ {{\dfrac{x}{8}e^{-\dfrac{x+y}{2}}    \,\,\,\,0 \leq x,0\leq y \atop {0}} \right.

So the marginal function for X is given as

f_x=\int\limits^{\infty}_0 {f(x,y)} \, dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x+y}{2} }dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x}{2}}e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{8}e^{-\frac{x}{2}}\int\limits^{\infty}_0e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{4}e^{-\frac{x}{2}}

Now

f(Y/X)=\dfrac{f(X,Y)}{f(X)}\\f(Y/X)=\dfrac{\dfrac{x}{8}e^{-\frac{x+y}{2} }}{\dfrac{x}{4}e^{-\frac{x}{2}}}\\f(Y/X)=\dfrac{1}{2}e^{-\frac{y}{2} }

Now the value of E(Y/X) is given as

E(Y/X)=\int\limits^{\infty}_0 {yf_{Y/X}} \, dy \\E(Y/X)=\int\limits^{\infty}_0 {y\dfrac{1}{2}e^{-\frac{y}{2} } }\, dy\\E(Y/X)=\dfrac{1}{2}\dfrac{\sqrt{2}}{(\dfrac{1}{2})^2}=2

So the value of E(Y/X) is 2.

3 0
3 years ago
What is x?<br> 7(x – 5) = 9x – 3
Mkey [24]

Answer:

x = -16

Step-by-step explanation:

7(x-5) =9x-3 \\7x -35 = 9x - 3\\3- 35 = 9x - 7x\\-32 = 2x\\x = \frac{-32}{2}\\\huge \red{\boxed{x = -16}}

4 0
2 years ago
Read 2 more answers
Choose the fragment which best completes the following sentence. Your credit history will help government agencies determine if
katovenus [111]
Either C or B because your credit helps alot with your home and also helps with credit cards. I'm leaning more towards C though.
6 0
3 years ago
The point (2, –4) is reflected across the line y = –1. What are the coordinates of the image?
schepotkina [342]

ANSWER

The coordinates of the image are (2,2)

EXPLANATION

The mapping for a reflection across the line y=k is :

(x,y)\to (x,2k-y)

We want to find the image of the point (2,-4) after a reflection in the line y=-1.

In this case k=-1.

(2, - 4)\to (2,2( - 1)- - 4)

This simplifies to,

(2, - 4)\to (2, - 2 + 4)

(2, - 4)\to (2, 2)

Hence the image is (2,2)

4 0
3 years ago
A woman bought some large frames for $18 each and some small frames for $4 each at a closeout sale. If she bought 16 frames for
AleksandrR [38]

Answer:

$10

Step-by-step explanation:

8 0
2 years ago
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