Answer:![\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]](https://tex.z-dn.net/?f=%5Cvec%7Bv_R%7D%3D%5Chat%7Bi%7D%5B-329.11%5D%2B%5Chat%7Bj%7D%5B516.18%5D)
Explanation:
Given
Plane is initially flying with velocity of magnitude 
at angle of 
with North towards west
Velocity of plane airplane can be written as
Now wind is encountered with speed of 
at angle of 
resultant velocity
![\vec{v_R}=\hat{i}[-385.67+56.56]+\hat{j}[459.62+56.56]](https://tex.z-dn.net/?f=%5Cvec%7Bv_R%7D%3D%5Chat%7Bi%7D%5B-385.67%2B56.56%5D%2B%5Chat%7Bj%7D%5B459.62%2B56.56%5D)
for direction 
west of North
The horizontal force applied is 160 N while the velocity is 2.03 m/s.
<h3>What is the speed of the car?</h3>
The work done by the car is obtained as the product of the force and the distance;
W = F x
F = ?
x = 30.0 m
W = 4,800 J
F = 4,800 J/30.0 m
F = 160 N
But F = ma
a = F/m
a = 160 N/2.30 ✕ 10^3-kg
a= 0.069 m/s
Now;
v^2 = u^2 + 2as
u = 0/ms because the car started from rest
v = √2as
v = √2 * 0.069 * 30
v = 2.03 m/s
Learn more about force and work:brainly.com/question/758238
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London, it has hosted the 1908, 1948 and the 2012 summer olympics
Answer:
a) No. If air resistance is ignored the acceleration of the ball is the same at each point on its flight.
(b). No. As long as the air resistance is negligible, the acceleration of the ball at the top of its flight different from its acceleration just before it lands.
Explanation:
This constant, similar acceleration is called the acceleration due to gravity and it is the acceleration of a body due to the influence of the pull of gravity alone.
Every object on the surface of the earth regardless of its mass is pulled towards the centre of the earth, especially when in flight. Whether flying upwards, or coming downwards, the pull of attraction towards the surface of the earth is the same!
Posiible units of speed and velocity aare miles per hour
