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Bumek [7]
3 years ago
12

A batter hits a pop fly straight up. (a) Is the acceleration of the ball on the way up different from its acceleration on the wa

y down? (b) Is the acceleration of the ball at the top of its flight different from its acceleration just before it lands?
Physics
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer:

a) No. If air resistance is ignored the acceleration of the ball is the same at each point on its flight.

(b). No. As long as the air resistance is negligible, the acceleration of the ball at the top of its flight different from its acceleration just before it lands.

Explanation:

This constant, similar acceleration is called the acceleration due to gravity and it is the acceleration of a body due to the influence of the pull of gravity alone.

Every object on the surface of the earth regardless of its mass is pulled towards the centre of the earth, especially when in flight. Whether flying upwards, or coming downwards, the pull of attraction towards the surface of the earth is the same!

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Answer:

0.25miles/min

Explanation:

Instantaneous speed of a person or an object is its speed at a particular moment usually at a period of time.

The speedometer of a car reports the instantaneous speed.

 It can be mathematically expressed as;

        Instantaneous speed  = \frac{distance}{time}

At 20min the distance covered is 5miles;

    Instantaneous speed  = \frac{5 miles }{20mins}   = 0.25miles/min

8 0
3 years ago
A car has a force of 2000N and a mass of<br> 1000kg. What is the acceleration of the<br> car?
yan [13]

Answer:

100

Explanation:

by dividing 2000N and 1000kg.

5 0
4 years ago
Which kind of cloud touches the ground making it hard to see
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3 years ago
A uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from re
spayn [35]

The magnitude of the electric field can be calculated using the equation

E = \frac{F}{q}, where F is the Force acting on the proton and q is the charge of the proton.

We know that the charge of the proton is q = 1.6 x 10^{-19}  C

We have to calculate the Force first.

We know that F = ma from Newton's 2nd law, where m is the mass of the proton and a is the acceleration.

We know that the mass of the proton m = (1.67) X 10^{-27}  kg

So it turns out that we have to calculate acceleration before anything else.

In order to calculate the acceleration, we make use of the following data from the question:

Initial Velocity of the proton V_{i}  = 0

Distance traveled  D = 1.70 cm = 0.017 m

Time taken for the travel between the plates t = (1.48) X 10^{-6}  s

Acceleration a = ?

Using the equation, D = V_{i}t + \frac{1}{2} at^{2}, we get

Knowing that initial velocity is 0, the equation reduces to D = \frac{1}{2}at^{2}

Rearranging the equation so as to make a the subject of the formula, we have

a = \frac{2D}{t^{2} }

Plugging in the numbers and simplifying gives us a = 1.5 x 10^{10}   m/s^{2}

We can now calculate the Force using F = ma

Plugging in the known values, we get F = 2.5 x 10^{-17}  N

Using this, we can calculate E through the equation E = \frac{F}{q}

Plugging the numbers and simplifying gets us E = 156.25 N/C

Thus, the magnitude of the electric field between the plates of the capacitor is 156.25 N/C


B) To calculate the Final Velocity of the proton, we can make use of the equation

V_{f}  = V_{i}  + at

Plugging the numbers in and simplifying gets us V_{f}  = (2.22)  *  10^{4}  m/s

5 0
4 years ago
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D is your answer sill glad to help!
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