A long, straight wire carrying a current of 2.60 A is placed along the axis of a cylinder of radius 0.500 m and a length of 4.25
1 answer:
You might be interested in
Answer:
T = 365.58 K
Explanation:
Given that,
The concentration of solution, C = 0.750M
Osmotic pressure, P = 22.5 atm
We need to find the temperature of the solution.
The formula for the osmotic pressure is given by :
Where
R is gas constant,
So, the temperature of the solution is 365.58 K.
The radius of the wire loop is 
, so the area enclosed by the loop is
Initially, the magnetic field intensity is B=5.0 mT=0.005 T, so the magnetic flux throug the wire loop is
Initially, the magnetic field intensity is B=5.0 mT=0.005 T, so the magnetic flux throug the wire loop is