A long, straight wire carrying a current of 2.60 A is placed along the axis of a cylinder of radius 0.500 m and a length of 4.25
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Answer:
The minimum value is
Explanation:
From the question we are given that
The voltage is
The internal resistance is
The objective of this solution is to obtain the minimum value of the voltmeter resistance for which the voltmeter reading is within 1.0% of the emf of the battery
What is means is that we need to obtain voltmeter resistance such that
V = (100% -1%) of E
Where E is the e.m.f of the battery and V is the voltmeter reading
i.e V = 99% of E = 0.99 E = 7.425
Generally
E = V + ir
where ir is the internal potential difference of the voltmeter and
V is the voltmeter reading
Making i the subject of the formula above
Now the current is constant through out the circuit so,
Where is the value of voltmeter resistance
Hence