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BabaBlast [244]
3 years ago
13

two terms of an arithmetic sequence are a6= 40 and a20= -16. write and explicit rule for the nth term

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0

Answer:

Tn = 64-4n

Step-by-step explanation:

The nth term of an AP is expressed as:

Tn = a+(n-1)d

a is the common difference

n is the number of terms

d is the common difference

Given the 6th term a6 = 40

T6 = a+(6-1)d

T6 = a+5d

40 = a+5d ... (1)

Given the 20th term a20 = -16

T20 = a+(20-1)d

T20 = a+19d

-16 = a+19d... (2)

Solving both equation simultaneously

40 = a+5d

-16 = a+19d

Subtracting both equation

40-(-16) = 5d-19d

56 = -14d

d = 56/-14

d = -4

Substituting d = -4 into equation

a+5d = 40

a+5(-4) = 40

a-20 = 40

a = 20+40

a = 60

Given a = 60, d = -4, to get the nth term of the sequence:

Tn = a+(n-1)d

Tn = 60+(n-1)(-4)

Tn = 60+(-4n+4)

Tn = 60-4n+4

Tn = 64-4n

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3 years ago
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The sum of three consecutive integers is 90. Find the three numbers by letting x
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Answer:

x = 28

Step-by-step explanation:

let us take three consecutive numbers be (x + 1), (x + 2) and (x + 3)

Now,

The sum of three consecutive integers is 90

i.e.,

(x + 1) + (x + 2) + (x + 3) = 90

x + 1 + x + 2 x + 3 = 90

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3x = 90 - 6

3x = 84

x = 84/3

x = 28

x = 28Thus, The value of x is 28

<h2><em><u>VERIFICATION</u></em><em><u>:</u></em></h2>

(x + 1) + (x + 2) + (x + 3) = 90

(28 + 1) + (28 + 2) + (28 + 3) = 90

28 + 1 + 28 + 2 + 28 + 3 = 90

90 = 90

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